Jersey測試框架中的UnrecognizedPropertyException

Question

我是Jersey測試框架的新手。 我正在嘗試在項目中使用jersey測試框架來實現測試用例。 我有一個REST服務，其網址將是：

http://localhost:8080/EzSupportBackend/a/dealerservices/getdealerdetails/FAB/ACZOKuBmtvyni16eMJ3AoSVg_HxL3bh3Lz0WiWNJhXudh9M90LSc8bDHD-Y2JpcbISZcC_DM2PL4yqSsmXUKA65ZmvuoiQ_wotgU1OvA8GGw_yPMwVnXGg==

我嘗試使用以下代碼使用Jersey測試此服務：

public class DealerServicesTest extends JerseyTest{
@Override
protected AppDescriptor  configure() {
    return new WebAppDescriptor.Builder().build();
}

@Test
public void testGetDealerDetails() throws JSONException,URISyntaxException {
    WebResource webResource = client().resource("http://localhost:8080/");
    JSONObject json = webResource.path("EzSupportBackend/a/dealerservices/getdealerdetails/FAB/ACZOKuBmtvyni16eMJ3AoSVg_HxL3bh3Lz0WiWNJhXudh9M90LSc8bDHD-Y2JpcbISZcC_DM2PL4yqSsmXUKA65ZmvuoiQ_wotgU1OvA8GGw_yPMwVnXGg==").get(JSONObject.class);

    assertEquals("ONLINE", json.get("companyType"));
    assertEquals("FabFurnish", json.get("companyName"));        
    assertEquals("Gurgoan,Haryana, India", json.get("companyAddress"));
    assertEquals("04222456803", json.get("phoneNumber"));
    assertEquals("ACTIVE", json.get("status"));     
    assertEquals("customerservice@fabfurnish.com", json.get("emailId"));
}
}

當我通過Postman（Chrome擴展程序）測試服務時，我得到如下正確答復：

{
  "companyType": "ONLINE",
  "companyName": "FabFurnish",
  "companyAddress": "Gurgoan,Haryana, India",
  "companyLocation": null,
  "longitude": "77.023419",
  "phoneNumber": "04222456803",
  "serviceRating": 0,
  "repairRating": 0,
  "warrantyRating": 0,
  "shopRating": 0,
  "status": "ACTIVE",
  "createdOn": 1446613095557,
  "updatedOn": 1446613095557,
  "companyId": "FAB",
  "lattitde": "28.47427",
  "emailId": "customerservice@fabfurnish.com",
  "createdby": null,
  "updatedby": null
}

但是通過此測試，我得到以下異常：

com.sun.jersey.api.client.ClientHandlerException:     com.fasterxml.jackson.databind.exc.UnrecognizedPropertyException: Unrecognized field "companyType" (class org.json.JSONObject), not marked as ignorable (0 known properties: ])
 at [Source: sun.net.www.protocol.http.HttpURLConnection$HttpInputStream@45b4c3a9; line: 1, column: 17] (through reference chain: org.json.JSONObject["companyType"])
    at com.sun.jersey.api.client.ClientResponse.getEntity(ClientResponse.java:563)
    at com.sun.jersey.api.client.ClientResponse.getEntity(ClientResponse.java:506)
    at com.sun.jersey.api.client.WebResource.handle(WebResource.java:674)
    at com.sun.jersey.api.client.WebResource.get(WebResource.java:191)
    at com.vs.mhs.ezsupport.services.DealerServicesTest.testGetDealerDetails(DealerServicesTest.java:27)

任何人都可以幫助我找出原因嗎？

編輯：我的代碼如下所示：

@PermitAll
@GET
@Path("/getdealerdetails/{companyId}/{token_id}")
public Response getDealerDetails(@PathParam("companyId") String companyId, @Context SecurityContext userContext, @Context HttpServletRequest request){
    boolean isUserAuthorised = isUserAuthenticated(userContext);
    DealerDetails dealer = null;
    DealerDetailsView getDealerView = null;
    if(isUserAuthorised){
        EntityManager em = (EntityManager) request.getAttribute(FilterConstants.ENTITYMANAGER);
        DealerDetailsBDL dealerbdl = new DealerDetailsBDL(em);
        dealer = dealerbdl.getDealerDetails(companyId);
        getDealerView = new DealerDetailsView(dealer);
    }
    return Response.ok(getDealerView).build();          
}

DealerDetailsView是一個具有私有變量的類，用於下面列出的屬性以及getter和setter：

private String companyid;
private String companyType;
private String companyName;
private String companyAddress;
private String companyLocation;
private String lattitude;
private String longitude;
private String phoneNumber;
private String emailid;
private int serviceRating;
private int repairRating;
private int warrantyRating;
private int shopRating;
private String status;

Answer 1

Jackson是JSON提供程序，Jackson通常使用模型POJO，而JSONObject不是。 傑克遜（Jackson）正在JSONObject尋找companyType屬性，而該屬性沒有。 這就是為什么您要獲得例外。 如果您沒有專門用於該JSON的POJO，則只需將其作為字符串獲取，然后使用該字符串創建JSONObject

String jsonString = webResource...get(String.class);
JSONObject json = new JSONObject(jsonString);

---

更新

Jackson的POJO只是一個將JSON字段映射到類屬性的類（遵循JavaBean命名約定）。 例如，對於這兩個JSON字段

"companyType": "ONLINE",
"companyName": "FabFurnish"

你可以像

public class CompanyInfo {
    private String companyType;
    private String companyName;

    public CompanyInfo() {}

    public String getCompanyInfo() { return companyInfo; }
    public void setCompanyInfo(String info) { this.companyInfo = info; }

    public String getCompanyType() { return companyType; }
    public void setCompanyType(String type) { this.companyType = type; }
}

為了使JSON字段與Java屬性匹配，屬性（getter / setter）應以get/set和字段的確切名稱為前綴，首字母大寫，如上所示。 因此，只需使用其他所有JSON字段完成POJO，然后序列化就可以與CompanyInfo 。