多維數組按Java中的列排序

Question

我需要此問題的幫助，共有三列，分別是phase＃，block＃和lot＃，我需要按升序對phase＃進行排序，而其他兩列將根據其phase＃進行相應排序：

問題：

階段1-2-1-3-1-2-1

編號1-1-2-1-2-1-1

編號1-2-2-2-3-1-1

它應該是什么樣的：

階段1-1-1-1-2-2-3

區塊＃1-2-2-1-1-1

第1-2-3-1-1-2號

這是到目前為止我得到的：

import java.io.*; 
import java.util.*;

public class test{
public static void main(String[] args) throws IOException{
    BufferedReader br = new BufferedReader(new InputStreamReader(System.in));

    int x = 7;
    int y = 3;
    int[][] phase= new int[x][y];
    int swap = 0, temp, i, min = 0;

     phase[0][0] = 1;
     phase[1][0] = 2;
     phase[2][0] = 1;
     phase[3][0] = 3;
     phase[4][0] = 1;
     phase[5][0] = 2;
     phase[6][0] = 1;
     phase[0][1] = 1;
     phase[1][1] = 1;
     phase[2][1] = 2;
     phase[3][1] = 1;
     phase[4][1] = 2;
     phase[5][1] = 1;
     phase[6][1] = 1;
     phase[0][2] = 2;
     phase[1][2] = 2;
     phase[2][2] = 2;
     phase[3][2] = 2;
     phase[4][2] = 3;
     phase[5][2] = 1;
     phase[6][2] = 1;

    System.out.println("UNSORTED: \n");
    System.out.println("Phase#\tBlock#\tLot#"); 
     for(i = 0; i < phase.length; i++){
        System.out.print(phase[i][0] + "\t" + phase[i][1] + "\t"+phase[i][2]);
        System.out.print("\n");
    }

    System.out.println("\nSORTED:\n");
    for(i = 0; i <= phase.length- 1; i++){
        min = i;
        for(int a = i+1; a < phase.length; a++ ){
            if(phase[a][0]<phase[a][0]){
                temp=phase[i][0];
                phase[i][0]=phase[a][0];
                phase[a][0]=temp;
            }
        }
    }
    System.out.println("Phase#\tBlock#\tLot#"); 
     for(int j = 0; j < phase.length; j++){
        System.out.print(phase[j][0] + "\t" + phase[j][1] + "\t"+phase[j][2]);
        System.out.print("\n");
    }

}

}

Answer 1

將Comparator接口實現為（向左int []，向右int []）->向左[0]-向右[0]，並將其傳遞給Arrays.sort（）方法：

Arrays.sort(phase, (int [] left, int[] right) -> left[0]-right[0]);