[英]using mutate_each from dplyr to convert all numeric variables to factor
我正在嘗試使用 dplyr 中的 mutate_each 來轉換因子中數據集的所有數字變量。
library(dplyr)
data(iris)
tbl_df(iris) ->iris
# I can transform all variables in factor
iris %>% mutate_each(funs(as.factor)) %>% summary
# I can transform some variables in factor
iris %>% mutate_each(funs(as.factor),one_of("Sepal.Length", "Petal.Length")) %>% summary
但我的目標是將所有數字變量轉換為因子,所以我嘗試這樣做:
iris %>% mutate_each(funs(as.factor),sapply(iris,is.numeric)) %>% summary # should be a good way, but it doesn't
再試一次
iris %>% mutate_each(funs(as.factor),one_of(names(iris)[sapply(iris,is.numeric)]))
# Error in one_of(vars, ...) : object 'iris' not found
iris %>% mutate_each(funs(as.factor),names(iris)[sapply(iris,is.numeric)])
#Error in one_of(vars, ...) : object 'iris' not found
# anyway the one_of function dont seems to work in mutate_each
vars<-names(iris)[sapply(iris,is.numeric)]
iris %>% mutate_each_(funs(as.factor),one_of(c("Petal.Length", "Petal.Width")))
iris %>% mutate_each_(funs(as.factor),one_of(vars))
# Without %>% This works
mutate_each(iris,funs(as.factor), one_of(c("Petal.Length", "Petal.Width"))) %>% summary
這很奇怪..有什么想法嗎??
謝謝
今天更好的解決方案應該是:
iris %>% mutate_if(is.numeric,as.factor)
dplyr 1.06 版及更早版本的更新答案(在此之前也有一點,但我忘記了版本)
iris %>%
mutate(across(where(is.numeric) , as.factor))
mutate_if()
和其他)已經通過取代across()
或across()
/ where()
發生變異內組合。
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