如何從php中的json_decode獲取ID

Question

我正在嘗試通過使用json_decode函數從json獲取所有ID，如何才能僅在數組中獲得ID？ 我非常感謝您的幫助。

響應：

{
  "columns": [
    "name",
    "id",
    "sno"
  ],
  "data": [
    [
      "test1",
      "123",
      "1"
    ],
    [
      "test2",
      "456",
      "2"
    ]
  ]
}

碼：

$obj = json_decode($result, true);
foreach ($obj as $key => $value) {
    foreach ($value as $k => $val) {
        echo $val;
        if ($k == "id") {
            array_push($all_ids, $val);
        }
    }
}

Answer 1

$obj     = json_decode($result);
$all_ids = array();

foreach ($obj->data as $el) {
  array_push($all_ids, $el[1]);
}

Answer 2

您可以使用in_array和array_map如下進行操作 ：

$obj = json_decode($result);
// identify which column number corresponds to "id"
$idColumnNo = in_array('id', $obj->columns);
// collect the elements at that column number from the data array
$all_ids = array_map(function ($elem) {
    return $elem[$idColumnNo];
}, $obj->data);

Answer 3

array_map()

$ids = array_map(function($a){return $a[1];}, $obj['data']);