在數組中搜索char

Question

我正在創建一個Java程序，並且堅持在數組中搜索char的概念。

該代碼用於創建一個子手游戲，其中一部分將顯示需要猜測的單詞長度的部分完成的，子手，一個字母和一組空格（“ _”）。 每次猜測之后，我需要從字母表中猜出字母（這是我現在正在使用的部分），如果是正確的猜測，請用該字母替換單詞中的空白，或者如果輸入錯誤猜猜，完成另一條子手。

我只創建了代碼來搜索數組中的數字，而不是char。 我一直在瀏覽我的書和互聯網，但找不到解決方案。

沒人知道這樣做的方法還是我在哪里可以找到方法？

抱歉，我已經發布了有關此作業的問題，但是要在幾天內完成，所以我很努力。

到目前為止，這是我的代碼（我苦苦掙扎的部分在最底部）：

public static void main(String[] args)
{
    String[] words =
    {
        "javascript", "declaration", "object", "program", "failing"
    };
    //generate random word from list
    Random rnd = new Random();

    String rndWord = words[rnd.nextInt(words.length)];

    //gets length of generated word
    char[] displayArray = new char[rndWord.length()];
    //displays "_" for number of chars in word
    for (int i = 0; i < rndWord.length(); i++)
    {
        displayArray[i] = '_';
    }

    char[] alphabet =
    {
        'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j',
        +'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v', 'w',
        +'x', 'y', 'z'
    };
    String hangman
            = "Let's Play Hangman!!" + "\n"
            + "-------------" + "\n"
            + "|" + "\n"
            + "|" + "\n"
            + "|" + "\n"
            + "|" + "\n"
            + "|" + "\n"
            + "|" + "\n"
            + "|" + "\n"
            + "|" + "\n"
            + "\n" + Arrays.toString(displayArray) + "\n"
            + "       ";

    JOptionPane.showMessageDialog(null, hangman + " "
            + Arrays.toString(alphabet) + " ");
}

//get letter
public static char guess()
{
    String guessStr = JOptionPane.showInputDialog("Enter a letter to guess: ");

    // check if have at least one letter
    if (guessStr.length() > 0)
    {

    }
    char guessChar = guessStr.charAt(0);
    return guessChar;
}

//remove guess from alphabet
private char[] getCharArray(char[] array)
{
   //this is the part I'm not sure about
}

Answer 1

您可以使用contains()方法在列表中找到字符。 通過char c = guessStr.toLowerCase().toCharArray()[0];獲取字符char c = guessStr.toLowerCase().toCharArray()[0]; 來自玩家輸入的guessStr 。 並通過if (guessedCharList.contains(new Character(c)))在List中搜索它。 列表只能存儲對象，因此我們必須通過new Character(c)將char基本類型轉換為對象Character 。

在下面的代碼將幫助您！ 但是您應該對此進行優化。

import java.util.ArrayList;
import java.util.Arrays;
import java.util.List;
import java.util.Random;

import javax.swing.JOptionPane;

public class HangMan {

    private static List<Character> guessedCharList = new ArrayList<Character>();
    private static List<Character> validCharList = new ArrayList<Character>();
    private static String rndWord = null;

    private static int numberOfWrongGuess = 0;

    public static void main(String[] args) {
        String[] words = { "javascript", "declaration", "object", "program",
                "failing" };
        // generate random word from list
        Random rnd = new Random();

        rndWord = words[rnd.nextInt(words.length)];
        System.out.println(rndWord);
        // gets length of generated word
        char[] displayArray = new char[rndWord.length()];
        // displays "_" for number of chars in word

        for (int i = 0; i < rndWord.length(); i++) {
            displayArray[i] = '_';
        }
        char[] alphabet = { 'a', 'b', 'c', 'd', 'e', 'f', 'g', 'h', 'i', 'j',
                +'k', 'l', 'm', 'n', 'o', 'p', 'q', 'r', 's', 't', 'u', 'v',
                'w', +'x', 'y', 'z' };

        String hangman = null;
        boolean finished = false;
        do {

            hangman = "Let's Play Hangman!!" + "\n" + "-------------" + "\n"
                    + "|" + "\n" + "|" + "\n" + "|" + "\n" + "|" + "\n" + "|"
                    + "\n" + "|" + "\n" + "|" + "\n" + "|" + "\n" + "\n"
                    + Arrays.toString(displayArray) + "\n" + "       ";

            JOptionPane.showMessageDialog(null,
                    hangman + " " + Arrays.toString(alphabet) + " ");
            guess();

            for (int i = 0; i < rndWord.length(); i++) {

                if (validCharList.contains(rndWord.charAt(i)))
                    displayArray[i] = rndWord.charAt(i);
                else
                    displayArray[i] = '_';
            }

            for (char c : displayArray) {
                if (c == '_') {
                    finished = false;
                    break;
                } else
                    finished = true;
            }

            if (numberOfWrongGuess >= 5) { // 5 wrong guess: "he was hanged."
                JOptionPane.showMessageDialog(null, "Man was hanged!");
                finished = true;
            }
        } while (!finished);

        hangman = "Let's Play Hangman!!" + "\n" + "-------------" + "\n" + "|"
                + "\n" + "|" + "\n" + "|" + "\n" + "|" + "\n" + "|" + "\n"
                + "|" + "\n" + "|" + "\n" + "|" + "\n" + "\n"
                + Arrays.toString(displayArray) + "\n" + "       ";
        JOptionPane.showMessageDialog(null,
                hangman + " " + Arrays.toString(alphabet) + " ");
    }

    // get letter
    public static String guess() {
        String guessStr = "";

        while (guessStr == null || guessStr.trim().isEmpty()
                || guessStr.length() > 1) {
            guessStr = JOptionPane.showInputDialog("Enter a letter to guess: ");
        }

        char c = guessStr.toLowerCase().toCharArray()[0];

        if (guessedCharList.contains(new Character(c))) {
            JOptionPane
                    .showMessageDialog(null, "You already give that answer!");
            guess();
        }

        guessedCharList.add(new Character(c));

        if (rndWord.contains(c + "")) {
            validCharList.add(new Character(c));
            return c + "";
        } else {
            numberOfWrongGuess++;
            return "";
        }
    }
}

Answer 2

問題是數組初始化后無法更改大小。 一些解決方案是：

您可以使用一個列表（例如java.utils.ArrayList）。 這樣，您就可以動態搜索和刪除條目。

另一種可能性是使用一個不使用的字符，例如“-”。 您可以替換字符，而不是刪除條目。 這樣，您必須在訪問陣列時進行檢查。

Answer 3

import java.util.HashMap;
import java.util.Map;

public class MatchingWordsInStream {
 Map < String, Integer > map;
 String input;
 char arr[];
 int valueArr[];
 StringBuffer stringArr[];
 int space = 1;
 public MatchingWordsInStream(String input) {
  this.input = input;
 }
 public void initialiseCharArray() {
  arr = new char[input.length()];
  for (int i = 0; i < input.length(); i++) {
   arr[i] = input.charAt(i);
   if (arr[i] == ' ') space++;
  }
 }
 public void rCharCalculate() {
  stringArr = new StringBuffer[space];
  valueArr = new int[space];
  stringArr[0] = new StringBuffer();
  int index = 1;
  for (int i = 0; i < input.length(); i++) { //this loop make string array char
   ch = arr[i];
   if (ch == ' ') {
    stringArr[index] = new StringBuffer();
    ++index;
   } else {
    stringArr[index - 1] = stringArr[index - 1].append(arr[i]);
   }
  }
  for (int k = 0; k < stringArr.length; k++) {
   StringBuffer s = stringArr[k];
   for (int j = 0; j < stringArr.length; j++) {
    if (s.toString().equals(stringArr[j].toString())) {
     valueArr[k] += 1;
    }
   }
  }
 }
 public void result() {
  map = new HashMap < String, Integer > ();
  for (int i = 0; i < stringArr.length; i++) {
   map.put(stringArr[i].toString(), valueArr[i]);
  }
  System.out.println(map);
 }
 public static void main(String[] args) {
  MatchingWordsInStream obj = new MatchingWordsInStream("$INDIAN$ wangi bk. wangi bk. 1010 0101 0101 hi hi ii ii ii ii");
  obj.initialiseCharArray();
  //make string to char array
  obj.rCharCalculate();
  obj.result();
  //just for display
 }
}
}

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