JAXB - 從url解組

Question

我正在嘗試從這個網站顯示游戲的標題和ID： http ：//thegamesdb.net/api/GetGame.php？id = 2

當我從這個網址解組時： http ： //www.w3schools.com/xml/note.xml一切都好，但這里只有一個對象，而不是列表。 所以我現在遇到問題。 我正在閱讀谷歌的一些教程和示例，我制作了這段代碼：

Data.java：

@XmlRootElement( name = "Data" )
@XmlAccessorType (XmlAccessType.FIELD)
public class Data {
    @XmlElement(name = "Game")
    List<Game> games;

    public List<Game> getGames() {
        return games;
    }

    public void setGames(List<Game> games) {
        this.games = games;
    }
}

Game.java文件：

@XmlRootElement(name = "Game")
@XmlAccessorType (XmlAccessType.FIELD)
public class Game {
    private int id;
    private String gameTitle;

    public int getId(){
        return id;
    }

    public void setId(int id){
        this.id = id;
    }

    public String getGameTitle(){
        return gameTitle;
    }

    public void setGameTitle(String gameTitle){
        this.gameTitle = gameTitle;
    }
}

控制器：

@RequestMapping(value = "/", method = RequestMethod.GET)
public ModelAndView home(Locale locale) throws MalformedURLException {
    ModelAndView model = new ModelAndView("index");
    JAXBExample test = new JAXBExample();
    Game customer = test.readXML();
    model.addObject("customer", customer);
    return model;
}

JAXBExample.java：

public class JAXBExample {
    public Game readXML() throws MalformedURLException {
        Data customer = null;
        Game game = null;
        try {
            JAXBContext jaxbContext  = JAXBContext.newInstance(Data.class);
            URL url = new URL("http://thegamesdb.net/api/GetGame.php?id=2");
            Unmarshaller jaxbUnmarshaller = jaxbContext.createUnmarshaller();
            customer = (Data) jaxbUnmarshaller.unmarshal(url);
            List<Game> games = customer.getGames();
            game = games.get(0);
        } catch (JAXBException e) {
            e.printStackTrace();
        }
        return game;
    }
}

和index.jsp：

<%@ taglib uri="http://tiles.apache.org/tags-tiles" prefix="tiles"%>

<tiles:insertDefinition name="defaultTemplate">
    <tiles:putAttribute name="body">
        Name: ${customer.gameTitle}<br />
        Id: ${customer.id}<br />
    </tiles:putAttribute>
</tiles:insertDefinition>

但我的代碼不起作用。 有人可能知道我做錯了什么？ 因為我得到了：

Name:
Id: 

僅此而已。

Answer 1

你的注釋唯一錯誤的是

public class Game {
  private int id;
  @XmlElement(name = "GameTitle") //You need to add this since first letter is uppercase, otherwise the GameTitle will not unmarshall.
  private String gameTitle; 
  ... your code ...
}

那么為什么其他工作呢？

服務器返回HTTP響應代碼：403為URL： http ： //thegamesdb.net/api/GetGame.php？id = 2

403 =禁止

解決方案 （讓服務器相信您是一個瀏覽器）

URL url = new URL("http://thegamesdb.net/api/GetGame.php?id=2");
HttpURLConnection http = (HttpURLConnection) url.openConnection(); 
http.addRequestProperty("User-Agent", "Mozilla/4.76"); 
InputStream is = http.getInputStream();
Unmarshaller jaxbUnmarshaller = jaxbContext.createUnmarshaller();
customer = (Data) jaxbUnmarshaller.unmarshal(is);
List<Game> games = customer.getGames();
game = games.get(0);

注意： Try catch final ，關閉流並檢查NullPointer是否超出此示例並且取決於用戶。