從SQL Server thorugh php獲取數據並使其以json格式

Question

我正在嘗試制作一個從SQL Server數據庫獲取其數據的UI。 我想通過PHP獲得它。 目前，我可以建立數據庫連接並通過以下代碼插入數據

 <?php $serverName = "esdapocnv01"; $connectionInfo = array( 'Database'=>'TRG_TEST', 'UID'=>'testuser', 'PWD'=>'Towing@2'); $conn = sqlsrv_connect( $serverName, $connectionInfo ); if( $conn === false ) { die( print_r( sqlsrv_errors(), true)); echo "Connection could not be established.<br />"; } $class = $_POST['number']; $teachers=$_POST['teachers1']; $rooms=$_POST['rooms1']; $sql = "insert into school(class,teachers,rooms) values ('$class','$teachers','$rooms') "; $stmt = sqlsrv_query( $conn, $sql ); if( $stmt === false) { die( print_r( sqlsrv_errors(), true) ); } while( $row = sqlsrv_fetch_array( $stmt, SQLSRV_FETCH_ASSOC) ) { echo "<option value='" . $row['station'] . "'>" . $row['station'] . "</option>"; } sqlsrv_free_stmt( $stmt); ?> 

現在，我想從數據庫表中獲取數據並將其轉換為JSON格式，以便可以在UI中使用它

Answer 1

$.ajax({
    url: "data1.php", 
    data: {"id": "EMP001"},
    success: function(result){

        var obj = jQuery.parseJSON( result );
        alert( obj.name );

    }
});

data1.php

<?php
    $id=$_REQUEST['id'];
    //fetch table rows from mysql db
    $sql = "SELECT * FROM `tbl_employee` WHERE `id`='$id'";
    $result = mysqli_query($connection, $sql) or die("Error in Selecting " . mysqli_error($connection));
    $emparray = array();
    while($row =mysqli_fetch_assoc($result)){
       $emparray[] = $row;
    }
    echo json_encode($emparray);
?>

Answer 2

<?php
    //fetch table rows from mysql db
    $sql = "select * from tbl_employee";
    $result = mysqli_query($connection, $sql) or die("Error in Selecting " . mysqli_error($connection));
    $emparray = array();
    while($row =mysqli_fetch_assoc($result)){
       $a['class']=$row['class'];
       $a['teacher']=$row['teachers'];
       $a['room']=$row['rooms'];
       $a['addedat']=Now(); //example of adding extra data if required
       $b[]=$a;
    }
    echo json_encode($b);
?>