[英]Error while creating a record through salesforce API
在運行以下代碼時,
private static void createAccounts() {
Itil_b__Incident__c[] records = new Itil_b__Incident__c[5];
try {
// create 5 test accounts
for (int i=0;i<1;i++) {
Itil_b__Incident__c a = new Itil_b__Incident__c();
a.setCurrencyIsoCode("USD");
a.setIsDeleted(Boolean.FALSE);
a.setItil_b__Age_Minutes__c(29d);
a.setHas_Managed_Services__c(Boolean.FALSE);
a.setItil_b__Priority_from_ITIL_Matrix__c("Medium");
a.setItil_b__Priority__c("Medium");
a.setItil_b__Description__c("Testing API Descrition");
a.setRank_Zero__c(Boolean.FALSE);
a.setItil_b__Close_With_Problem__c(Boolean.FALSE);
a.setItil_b__Subject__c("Test from API");
a.setItil_b__Origin__c("Phone");
a.setItil_b__Age__c("29 Days");
a.setItil_b__Status__c("New");
a.setAssigned_for_Today__c(Boolean.FALSE);
a.setItil_b__Urgency__c("P4 - Low");
a.setItil_b__Category__c("Request");
a.setItil_b__Impact__c("Low");
a.setSeverity__c("Sev4");
records[i] = a;
}
// create the records in Salesforce.com
SaveResult[] saveResults = connection.create(records);
// check the returned results for any errors
for (int i=0; i< saveResults.length; i++) {
if (saveResults[i].isSuccess()) {
System.out.println(i+". Successfully created record - Id: " + saveResults[i].getId());
} else {
Error[] errors = saveResults[i].getErrors();
for (int j=0; j< errors.length; j++) {
System.out.println("ERROR creating record: " + errors[j].getMessage());
}
}
}
} catch (Exception e) {
e.printStackTrace();
}
}
我在saveResults行中收到以下錯誤,
[InvalidSObjectFault [ApiQueryFault [ApiFault exceptionCode='INVALID_TYPE'
exceptionMessage='Must send a concrete entity type.'
]
row='-1'
column='-1'
]
]
我正在通過Java API在自定義sObject [Itil_b__Incident__c]中創建新記錄,能否請您幫助我可能丟失的內容?
檢查您的循環。 您當前擁有for (int i = 0; i < 1; i++) {
您的評論說您想創建5個對象,因此應該是for (int i=0; i<5; i++) {
。
另外,我對Java API不熟悉-我使用的是Python API。 通常情況下,由於我使用的是REST API,因此需要將對象序列化為JSON。 Java API是否會在create方法中為您自動進行JSON序列化? 您的Itil_b__Incident__c對象是否具有返回JSON字符串的toJson()方法?
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