CakePhp 3.x中的jQuery ajax發布無法在控制器中獲取數據

Question

我到處都看過了，由於某種原因，我無法通過ajax發布數據到我的控制器。

jQuery的：

        var newDate = {};
        newDate['start'] = startyear+"-"+startmonth+"-"+startday+" "+starthour+":"+startminute+":00";
        newDate['end'] = endyear+"-"+endmonth+"-"+endday+" "+endhour+":"+endminute+":00";
        newDate['allday'] = allday;
        console.log(JSON.stringify(newDate));
        var url = plgFcRoot + "events/update/"+event.id;
        $.ajax({
            type: 'POST',
            url: url,
            data: JSON.stringify(newDate),
            dataType: "json",
            contentType: "application/json; charset=utf-8",
        })
        .done( function( data ) {
            console.log( data );
        })
        .fail(function( data ) {
            console.log( data );
        });

字符串化時，我在控制台中得到了這個：

{"start":"2015-12-7 21:30:00","end":"2015-12-7 22:30:00","allday":0}

我試圖將數據發送回作為控制器的響應：

public function update($id = null)
{
    $event = $this->Events->get($id);
    $event = $this->Events->patchEntity($event, $this->request->data);
    $this->Events->save($event);
    $this->set(compact('event'));
    $this->response->body($this->request->data());
    return $this->response;
}

Answer 1

jQuery為您處理對傳遞給$ .ajax（）中“數據”的對象進行urlencoding。 這應該可以解決問題：

var newDate = {};
    newDate['start'] = startyear+"-"+startmonth+"-"+startday+" "+starthour+":"+startminute+":00";
    newDate['end'] = endyear+"-"+endmonth+"-"+endday+" "+endhour+":"+endminute+":00";
    newDate['allday'] = allday;
    console.log(JSON.stringify(newDate));
    var url = plgFcRoot + "events/update/"+event.id;
    $.ajax({
        type: 'POST',
        url: url,
        // NOTICE JSON.stringify() has been removed!
        data: newDate
    })
    .done( function( data ) {
        console.log( data );
    })
    .fail(function( data ) {
        console.log( data );
    });

或者，如果您100％希望將JSON作為請求正文傳遞，則可以使用請求上的輸入方法解碼數據：

public function update($id = null)
{
    $event = $this->Events->get($id);
    $request_data = $this->request->input('json_decode');
    $event = $this->Events->patchEntity($event, $request_data);
    $this->Events->save($event);
    $this->set(compact('event'));
    $this->response->body(json_encode($request_data));
    return $this->response;
}

我將進一步閱讀CakePHP 3的JSON和XML Views文檔 。

Answer 2

你可以試試這個

public function update($id = null)
{
    $event = $this->Events->get($id);
    $data = json_decode($this->request->data);
    $event = $this->Events->patchEntity($event, $data);
    $this->Events->save($event);
    $this->set(compact('event'));
    $this->response->body($this->request->data);
    return $this->response;
}