iOS應用程序中的日期和時間格式

Question

我從響應中獲取以下日期格式

2015-12-23 05:17:04

但是，我想檢查日期和時間，

日期==今天？ 日期==昨天？

時間== 1小時時間== 2小時至9小時

怎么做 ？

Answer 1

要檢查日期是今天，昨天，明天等，您可以使用NSDate-Extensions

例如：

NSDate *date = [self convertStringToDate:@"2015-12-24 12:40:04" formate:@"yyyy-MM-dd HH:mm:ss"];
NSLog(@"%d", [date isToday]);
NSLog(@"%d", [date isTomorrow]);
NSLog(@"%d", [date isYesterday]);

- (NSDate *)convertStringToDate: (NSString *)date formate:(NSString *)formate {
    NSDateFormatter *dateFormat = [[NSDateFormatter alloc] init];
    [dateFormat setLocale:[[NSLocale alloc] initWithLocaleIdentifier:@"en_US"]];
    [dateFormat setDateFormat:formate];
    return [dateFormat dateFromString:date];
}

Answer 2

 NSDate *date = [NSDate date]; NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init]; dateFormatter.dateFormat = [NSString stringWithFormat:@"yyyyMMddHHmmss"]; NSString *now = [dateFormatter stringFromDate:date]; 

您可以嘗試上面的代碼

最好的祝願

Answer 3

使用此方法可以將NSString帶回來。 您可以在方法中比較字符串或時間。

-(NSString* )AgoStringFromTime:(NSDate*)dateTime
{
    NSDictionary *timeScale = @{@"sec"  :@1,
                                @"min"  :@60,
                                @"hr"   :@3600,
                                @"day"  :@86400,
                                @"week" :@605800,
                                @"month":@2629743,
                                @"year" :@31556926};
    NSString *scale;
    int timeAgo = 0-(int)[dateTime timeIntervalSinceNow];

    if (timeAgo < 60) {
        scale = @"sec";
    } else if (timeAgo < 3600) {
        scale = @"min";
    } else if (timeAgo < 86400) {
        scale = @"hr";
    } else if (timeAgo < 605800) {
        scale = @"day";
    } else if (timeAgo < 2629743) {
        scale = @"week";
    } else if (timeAgo < 31556926) {
        scale = @"month";
    } else {
        scale = @"year";
    }

    timeAgo = timeAgo/[[timeScale objectForKey:scale] integerValue];
    NSString *s = @"";
    if (timeAgo > 1) {
        s = @"s";
    }

    return [NSString stringWithFormat:@"%d %@%@", timeAgo, scale, s];
}

Answer 4

1.frist您可以將字符串格式化為日期，例如：

+ (NSDate *)dateFromString:(NSString *)dateString {
if (!dateString) {
    return nil;
}

NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
[formatter setDateFormat: @"yyyy-MM-dd HH:mm:ss"];
[formatter setLocale:[NSLocale currentLocale]];
NSDate *date= [formatter dateFromString:dateString];

return date;
}

2.然后，您可以使用NSDate的方法，

+ (instancetype)date;//get current
- (NSTimeInterval)timeIntervalSinceDate:(NSDate *)refDate;//Returns the interval between the receiver and another given date.