[英]How to select sum of count of distinct values in mysql?
這是我的查詢:
SELECT
p.PRO_Id, p.PRO_Name,
COUNT(DISTINCT c.COM_Id) as commentCount,
COUNT(DISTINCT d.DIS_Id) AS disCount,
d.DIS_ThreadDesc,
dev.DEV_Name,
loc.LOC_Name,
d.USE_Id,
d.DIS_Date
FROM projects p
LEFT JOIN discussions d ON p.PRO_Id = d.PRO_Id
LEFT JOIN comments c ON d.DIS_Id = c.DIS_Id
LEFT JOIN developer dev ON p.DEV_Id=dev.DEV_Id
LEFT JOIN locality loc ON p.LOC_Id=loc.LOC_Id
WHERE p.PRO_Status=1
and d.DIS_Status=1
and c.COM_Status=2
GROUP BY p.PRO_Id
ORDER BY 3 desc LIMIT 3
我想得到的是commenCount(全部評論)和disCount(全部討論)的總和。
我這樣嘗試過-
sum(COUNT(DISTINCT c.COM_Id) + COUNT(DISTINCT d.DIS_Id)) AS totalResponse但沒有機會。
您可以同時添加COUNT
的結果:
SELECT
p.PRO_Id, p.PRO_Name,
COUNT(DISTINCT c.COM_Id) AS commentCount,
COUNT(DISTINCT d.DIS_Id) AS disCount,
COUNT(DISTINCT c.COM_Id) + COUNT(DISTINCT d.DIS_Id) AS totalResponse
d.DIS_ThreadDesc, dev.DEV_Name, loc.LOC_Name, d.USE_Id, d.DIS_Date
FROM projects p
...
或者使用子查詢:
SELECT sub.*,
commentCount + disCount AS totalResponse
FROM (
SELECT
p.PRO_Id, p.PRO_Name,
COUNT(DISTINCT c.COM_Id) as commentCount,
COUNT(DISTINCT d.DIS_Id) AS disCount,
d.DIS_ThreadDesc,
dev.DEV_Name,
loc.LOC_Name,
d.USE_Id,
d.DIS_Date
FROM projects p
LEFT JOIN discussions d ON p.PRO_Id = d.PRO_Id
LEFT JOIN comments c ON d.DIS_Id = c.DIS_Id
LEFT JOIN developer dev ON p.DEV_Id=dev.DEV_Id
LEFT JOIN locality loc ON p.LOC_Id=loc.LOC_Id
WHERE p.PRO_Status=1
and d.DIS_Status=1
and c.COM_Status=2
GROUP BY p.PRO_Id
) AS sub
ORDER BY commentCount LIMIT 3
請記住,您的SELECT
列表和GROUP BY
不匹配。 這將適用於MySQL
但不符合ANSI
標准。 您在兩個子句中都應具有相同的列表,或者對GROUP BY
中未指定的列使用聚合函數。 更多信息在這里 。
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