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SQL Query在同一列中查找值的乘積

[英]SQL Query to find the product of values in same column

面試問題之前問過。

給定一個包含boxName和value列的表,找到每個框的音量。 值字段具有立方體的長度,bredth和高度。 我需要乘以所有樹的尺寸。

如果需要計算總和,我可以使用groupby ,但此處需要產品

box1 = 12*13*1  = 156
box2 = 1*23*6   = 138
box3 = 12*1*20  = 240

+---------+-------+
| boxName | value |
+---------+-------+
| box1    |    12 |
| box1    |    13 |
| box1    |     3 |
| box2    |     1 |
| box2    |    23 |
| box2    |     6 |
| box3    |    12 |
| box3    |     1 |
| box4    |    30 |
+---------+-------+

嘗試這個

select EXP(SUM(LN(value))) As Product_val ,boxName
from yourTable
Group by boxName

注意: value <= 0 LOG將失敗。

當你有值<= 0時,請使用它。

SELECT
    boxName,
    CASE
       WHEN MinVal = 0 THEN 0
       WHEN Neg % 2 = 1 THEN -1 * EXP(ABSMult)
       ELSE EXP(ABSMult)
    END
FROM
    (
    SELECT
       boxName, 
       --log of +ve row values
       SUM(LN(ABS(NULLIF(Value, 0)))) AS ABSMult,
       --count of -ve values. Even = +ve result.
       SUM(SIGN(CASE WHEN Value < 0 THEN 1 ELSE 0 END)) AS Neg,
       --anything * zero = zero
       MIN(ABS(Value)) AS MinVal
    FROM
       yourTable
    GROUP BY
       boxName
    ) foo

提到這個答案

如果您知道每個框對於3個維度將具有正好3行,則可以使用row_number()分析函數來唯一標識3個維度,然后使用max(case ...)來提取3個維度並乘以它們:

select boxName,
       max(case when rn = 1 then value end) *
       max(case when rn = 2 then value end) *
       max(case when rn = 3 then value end) as volume
  from (select t.*,
               row_number() over (partition by t.boxName order by null) as rn
          from yourTable t)
 group by boxName

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