Lodash沒有方法“刪除”

Question

我正在從我的書中遵循有關websockets的示例：

var _ = require('lodash')
var ws = require('ws')
var clients = []

exports.connect = function(server) {
    var wss = new ws.Server({server: server})

    wss.on('connection', function(ws) {
        clients.push(ws)

        ws.on('close', function() {
            _.remove(clients, ws)
        })
    })
}

exports.broadcast = ...

上面的代碼片段將新的websocket客戶端添加到clients數組。 客戶端關閉連接時，會將其從列表中刪除。 我在_.remove(clients, ws)上遇到以下錯誤：

TypeError: Object function lodash(value) {
    // exit early if already wrapped, even if wrapped by a different `lodash` constructor
    if (value && typeof value == 'object' && value.__wrapped__) {
      return value;
    }
    // allow invoking `lodash` without the `new` operator
    if (!(this instanceof lodash)) {
      return new lodash(value);
    }
    this.__wrapped__ = value;
  } has no method 'remove'
    at WebSocket.<anonymous> (/home/user/Projects/socialapp/websockets.js:15:6)
    at WebSocket.EventEmitter.emit (events.js:117:20)
    at WebSocket.cleanupWebsocketResources (/home/user/Projects/socialapp/node_modules/ws/lib/WebSocket.js:926:10)
    at Socket.EventEmitter.emit (events.js:117:20)
    at net.js:441:14
    at process._tickCallback (node.js:415:13)

那絕對是我書中完成的方式，而且我不明白為什么我會收到該錯誤，因為remove方法確實存在。

編輯：我使用lodash訴3.10.1

Answer 1

可能與您的lodash版本有關。 嘗試通過以下方式進行操作：

var _ = require('lodash')
var ws = require('ws')
var clients = []

exports.connect = function(server) {
    var wss = new ws.Server({server: server})

    wss.on('connection', function(ws) {
        clients.push(ws)

        ws.on('close', function() {
            clients = _.without(clients, ws)
        })
    })
}

或者您也可以使用普通的舊JavaScript來簡單地執行相同操作

clients = clients.filter((client) => client !== ws);