[英]AngularJS: how to get the error status of $http
這是我的情況:
我的控制器就像:
var userData = $http(
{
method: "post",
url: "http://some-domain.com/t-app/mobile-data/login.php",
data : $scope.loginForm, //forms user object
headers: { 'Content-Type': 'application/x-www-form-urlencoded' }
});
userData.success(function (userdataobject)
{
$rootScope.status_id = userdataobject["status_id"];
});
我知道這只有在可以連接互聯網的情況下才有效。 我的問題是,在這種情況下,我如何知道錯誤狀態,例如“ 404”,或者如果互聯網連接不可用?
有status
字段(來自docs ):
// Simple GET request example:
$http({
method: 'GET',
url: '/someUrl'
}).then(
function successCallback(response) {
// this callback will be called asynchronously
// when the response is available
},
function errorCallback(response) {
// called asynchronously if an error occurs
// or server returns response with an error status.
if (response.status === 404)
{
//your code here
}
});
您的情況是:
$http(
{
method: "post",
url: "http://some-domain.com/t-app/mobile-data/login.php",
data : $scope.loginForm, //forms user object
headers: { 'Content-Type': 'application/x-www-form-urlencoded' }
})
.then(
function(response) {
$rootScope.status_id = userdataobject.data["status_id"];
},
function(response) {
if (response.status === 404) {
//your code here
}
}
);
關於您的示例:
var userData = $http({
method: "post",
url: "http://some-domain.com/t-app/mobile-data/login.php",
data : $scope.loginForm, //forms user object
headers: { 'Content-Type': 'application/x-www-form-urlencoded' }
});
userData.success(function (userdataobject) {
$rootScope.status_id = userdataobject["status_id"];
}).catch(function(errorResponse, status) {
console.error(errorResponse); //for debugging
if (errorResponse.status == 404) {
//Handle 404 error
}
//or if (status == 404) {}
});
errorResponse
將具有以下字段:
您的代碼可能是這樣的:
$http(
{
method: "post",
url: "http://some-domain.com/t-app/mobile-data/login.php",
data : $scope.loginForm, //forms user object
headers: { 'Content-Type': 'application/x-www-form-urlencoded' }
}).then(function successCallback(response) {
$rootScope.status_id = response["status_id"];
}, function errorCallback(response) {
console.error(response.status);
console.error(response.statusText);
});
通過這種方式,您可以控制成功和錯誤
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