在Ajax調用中解析JSON

Question

我從數據庫的查詢中得到了這個JSON響應：

[{
  "IMAGE": "",
  "NAME": "BEANS,LIMA,DRY",
  "NSN": " 8915005302173",
  "FIIG": "T113-J",
  "INC": "2153",
  "CRITICALY": "0",
  "TYPE_II": "4",
  "DEMIL": "a",
  "DATE": "2003-06-12",
  "ESD": ")",
  "PMIC": "a",
  "ADPEC": "0",
  "HMIC": "n",
  "HCC": "",
  "ENAC": "",
  "SUPPLIER": "Defense Supply Agenc",
  "CAGE": "54027",
  "PART_NUMBER": "0",
  "STAT": "a",
  "RNCC": "3",
  "RNVC": "1",
  "DAC": "4",
  "RNAAC": "zz",
  "SADC": "",
  "MSDS": "",
  "MOE": "ds",
  "USC": "i",
  "AAC": "h",
  "SOS": "sms",
  "UI": "lb",
  "UNIT_PRICE": "1",
  "QUP": "1",
  "CIIC": "u",
  "SLC": "0",
  "MGT_CTRL": "",
  "REP": "",
  "SUPPLY_PACKAGE_TYPE": "Fruits and Vegetables",
  "SPECIAL_FEATURES": "",
  "DEFINITION": "Note-Subsistance items which are specifically prepared for dietetic use are classified in Class 8940. Nondietetic foods, even though they bear the same approved item names as corresponding dietetic fo"
}]

我想只選擇NSN號碼。 這是Ajax調用：

$(document).ready(function(){
function show(){
    $.ajax({
        url:"getProducts",

        success:function(data){
            var d=data;
            $("#output").html(d);
        }
    });
}
show();
});

Answer 1

告訴$.ajax()方法通過添加dataType :'json'將返回的數據視為JSON 。 因為您的data將是一個具有數組的對象，該數組在第一個索引處有一個對象，您將使用data[0].PROPERTY訪問您的屬性。 例：

 $.ajax({
    url:"getProducts",
    dataType: 'json',
    success:function(data){
        var d=data[0];
        $("#output").html(d.NSN);
    }
});