[英]How to set float values as scientific notation in matplotlib?
我已經seaborn
了以下浮動結果:
[7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.3e-05, 7.4e-05, 7.3e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.3e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.3e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05]
繪制一個禁用了科學記數法的圖形,如下所示:
結果函數:
def result(values, time):
x = 0.000000000001
max = 0.000000001
min = 0.001
y = [(1.0*i*(max/min) for i in values]
return generate((y, time))
以及生成圖形的函數:
def generate(data_):
data, time = data_
img = StringIO.StringIO()
sns.set_style("darkgrid")
plt.plot(time, data)
plt.savefig(img, format=format_)
img.seek(0)
x = base64.b64encode(img.getvalue())
return x
以下資料告訴我, seaborn
默認情況下以科學計數法設置值。 但是在這種情況下,我有浮動結果。
如何防止數字在Python Matplotlib圖中更改為指數形式
浮動結果重要嗎?
我對flask
不熟悉,但我認為您的問題可能出在繪圖上,而不是其他問題。 讓我們剝離所有其他內容,僅保留劇情。 我將您的代碼簡化為:
import datetime
import matplotlib.pyplot as plt
import seaborn as sns
sns.set_style("darkgrid")
import numpy as np
%matplotlib inline
def generate(data_):
data, time = data_
plt.plot(time, data)
def result(values, time):
x = 0.000000000001
max = 0.000000001
min = 0.001
y = [ 1.0*i*(max/min) for i in values ]
return generate((y, time))
values = [7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05,
7.4e-05, 7.4e-05, 7.3e-05, 7.4e-05, 7.3e-05, 7.4e-05,
7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05,
7.4e-05, 7.4e-05, 7.3e-05, 7.4e-05, 7.4e-05, 7.4e-05,
7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05,
7.4e-05, 7.4e-05, 7.3e-05, 7.4e-05, 7.4e-05, 7.4e-05,
7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05,
7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05,
7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05, 7.4e-05,
7.4e-05, 7.4e-05]
time = [datetime.time(17, 44, 41), datetime.time(17, 45, 41),
datetime.time(17, 46, 41), datetime.time(17, 47, 41),
datetime.time(17, 48, 41), datetime.time(17, 49, 41),
datetime.time(17, 50, 41), datetime.time(17, 51, 41),
datetime.time(17, 52, 41), datetime.time(17, 53, 41),
datetime.time(17, 54, 41), datetime.time(17, 55, 41),
datetime.time(17, 56, 41), datetime.time(17, 57, 41),
datetime.time(17, 58, 41), datetime.time(17, 59, 41),
datetime.time(18, 0, 41), datetime.time(18, 1, 41),
datetime.time(18, 2, 41), datetime.time(18, 3, 41),
datetime.time(18, 4, 41), datetime.time(18, 5, 41),
datetime.time(18, 6, 41), datetime.time(18, 7, 41),
datetime.time(18, 8, 41), datetime.time(18, 9, 41),
datetime.time(18, 10, 41), datetime.time(18, 11, 41),
datetime.time(18, 12, 41), datetime.time(18, 13, 41),
datetime.time(18, 14, 41), datetime.time(18, 15, 41),
datetime.time(18, 16, 41), datetime.time(18, 17, 41),
datetime.time(18, 18, 54), datetime.time(18, 19, 55),
datetime.time(18, 20, 57), datetime.time(18, 21, 57),
datetime.time(18, 23, 3), datetime.time(18, 24, 27),
datetime.time(18, 25, 27), datetime.time(18, 26, 27),
datetime.time(18, 27, 27), datetime.time(18, 28, 27),
datetime.time(18, 29, 27), datetime.time(18, 30, 38),
datetime.time(18, 32, 4), datetime.time(18, 33, 12),
datetime.time(18, 34, 54), datetime.time(18, 35, 54),
datetime.time(18, 37, 34), datetime.time(18, 38, 34),
datetime.time(18, 40, 28), datetime.time(18, 41, 28),
datetime.time(18, 42, 28), datetime.time(18, 43, 28)]
result(values,time)
它以科學的表示法給了我結果:
嘗試使用此代碼,看看是否做出科學計數。 如果沒有,我敢打賭,您需要將matplotlib
和seaborn
更新到最新版本。 如果是這樣,那么至少您知道其他問題正在使您的標簽更加混亂。
使用matplotlib.ticker.FormatStrFormatter
解決了該問題
import matplotlib.ticker as mtick
def generate(data_):
data, time = data_
img = StringIO.StringIO()
sns.set_style("darkgrid")
plt.plot(time, data)
plt.gca().yaxis.set_major_formatter(mtick.FormatStrFormatter('%.1E')) #this line solves the problem
plt.savefig(img, format=format_)
img.seek(0)
x = base64.b64encode(img.getvalue())
return x
使用其他時間和值,我得到了該圖,並以科學計數法表示了yaxis。
請參閱此處的文檔
matplotlib.ticker.FormatStrFormatter(fmt)類
Bases: matplotlib.ticker.Formatter Use an old-style ('%' operator) format string to format the tick
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.