查找最頻繁的值和排序

Question

+-----------------------+------------------------+
| being_followed        | follower               |
+-----------------------+------------------------+
| Bob Dylan             |                      B |
| Bob Dylan             |                      A |
| Sam Cooke             |                      X |
| The Beatles           |                      Y |
| Bob Dylan             |                      M |
| Sam Cooke             |                      N |
+-----------------------+------------------------+

現在，我想在being_followed找到最出現的值，然后按它排序。 它看起來應該像-

Bob Dylan - 3
Sam Cooke - 2
The Beatles - 1

請不要將此標記為重復項。

Answer 1

請嘗試以下方法：

select being_followed , count(1) as count
from table
group by being_followed 
order by count desc ;

Answer 2

嘗試這個：-

select being_followed,count(*) total_followers
from table
group by being_followed
order by total_followers desc

Answer 3

SELECT being_followed , count(being_followed )as counter FROM `table_Name` GROUP BY being_followed ORDER BY counter DESC

您將得到想要的結果。在此處使用group by將獲得唯一值，在使用count時將獲得相同的being_followed計數器

Answer 4

嘗試這個：

SELECT being_followed,COUNT(*) AS follower 
FROM tablename GROUP BY being_followed ORDER BY follower DESC;

輸出：

+-----------------------+------------------------+
| being_followed        | follower               |
+-----------------------+------------------------+
| Bob Dylan             |                      3 |
| Sam Cooke             |                      2 |
| The Beatles           |                      1 |
+-----------------------+------------------------+

Answer 5

嘗試這個

SELECT being_followed,COUNT(1) count_followers
FROM table
GROUP BY being_followed
ORDER BY COUNT(1) DESC;

獲取being_followed的計數，並按從高到低的順序排序（降序）

Answer 6

也許您可以嘗試以下方法：

select being_followed, count(*) follower
from TableName
group by being_followed
order by follower desc

一切正常。