[英]Get values from table row
從下表可以使用Javascript / jquery / jquery-plugins獲得每種運動的總價值,例如:
足球:2板球:1網球:2
<!DOCTYPE html>
<html>
<body>
<table style="width:100%">
<thead>
<tr>
<td>first name</td>
<td>last name</td>
<td>sport</td>
</tr>
</thead>
<tr>
<td>Bob</td>
<td>Smith</td>
<td>football</td>
</tr>
<tr>
<td>Dan</td>
<td>Jackson</td>
<td>cricket</td>
</tr>
<tr>
<td>Will</td>
<td>Rie</td>
<td>Tennis</td>
</tr>
<tr>
<td>Tom</td>
<td>Lawrence</td>
<td>Tennis</td>
</tr>
<tr>
<td>John</td>
<td>croft</td>
<td>football</td>
</tr>
</table>
</body>
</html>
我試過使用Jquery .size()
和.count()
但沒有使其工作。 任何建議都會有所幫助!
創建一個對象,解析表以獲取所有最后的td
,獲取它們的值並將其設置為對象的鍵,並在它們再次出現時增加其值。
var sports = {}; $(function() { $("table tr:not(:first)").each(function(i) { var sport = $(this).find("td").last().text(); if (sports.hasOwnProperty(sport)) sports[sport] += 1; else sports[sport] = 1; }); console.log(sports); console.log("Football count is: " + sports.football); });
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <table style="width:100%"> <thead> <tr> <td>first name</td> <td>last name</td> <td>sport</td> </tr> </thead> <tr> <td>Bob</td> <td>Smith</td> <td>football</td> </tr> <tr> <td>Dan</td> <td>Jackson</td> <td>cricket</td> </tr> <tr> <td>Will</td> <td>Rie</td> <td>Tennis</td> </tr> <tr> <td>Tom</td> <td>Lawrence</td> <td>Tennis</td> </tr> <tr> <td>John</td> <td>croft</td> <td>football</td> </tr> </table>
這將循環遍歷各行(忽略第一行),並查看每行的最后一個td
,然后將count添加到counts
對象。 如果以前沒有看過這項運動,則將其包括在內,計數為1
,否則,它將僅增加已存在的一項。
編輯:添加了jsfiddle: https ://jsfiddle.net/1prura93/
$(document).ready(function() {
var rows = $('tr');
var counts = {};
var sport = null;
for (var i = 1; i < rows.length; i++) {
sport = $('td', rows[i]).last().text();
if (!counts[sport]) {
counts[sport] = 1;
} else {
counts[sport]++;
}
}
console.log(counts);
});
純JS解決方案。 如果特定表具有ID /類等,則可以獲取該表,然后在表上可能有多個表的情況下使用tableElement.getElementsByTagName('tr)。
var sports = {};
var rows = document.getElementsByTagName('tr');
for(var i = 1; i < rows.length; i++) {
var sport = rows[i].children[2].textContent;
if(sports[sport] === undefined) {
sports[sport] = 1;
}
else {
sports[sport] += 1;
}
}
我的建議是:
$(function() { var result = {}; $('table tr:not(:first)').find('td:last').each(function(index, element) { var txt = element.innerHTML; if (!result.hasOwnProperty(txt)) { result[txt] = 1; } else { result[txt]++; } }); var resultStr = JSON.stringify(result).replace(/[{}"]/g, '').replace(/,/g, ' '); alert(resultStr); });
<script src="http://code.jquery.com/jquery-1.11.3.js"></script> <table style="width:100%"> <thead> <tr> <td>first name</td> <td>last name</td> <td>sport</td> </tr> </thead> <tr> <td>Bob</td> <td>Smith</td> <td>football</td> </tr> <tr> <td>Dan</td> <td>Jackson</td> <td>cricket</td> </tr> <tr> <td>Will</td> <td>Rie</td> <td>Tennis</td> </tr> <tr> <td>Tom</td> <td>Lawrence</td> <td>Tennis</td> </tr> <tr> <td>John</td> <td>croft</td> <td>football</td> </tr> </table>
Javascript方法
//create an emppty object to hold your collection var collection={}; //find all td cells in the third columns and save it to a variable named third_column_value var third_column_value=document.getElementById('sport').querySelectorAll('tr td:nth-child(3)'); //loop through all third column objects for(var i=0;i<third_column_value.length;++i){ //if td object value (sport value ) is in collection add 1 to the sport value if( third_column_value[i].innerHTML in collection){ collection[third_column_value[i].innerHTML]+=1; } //if not add create a key name sport value and add 1 to it else{ collection[third_column_value[i].innerHTML]=1; } } //make it a string and put it in a pop up box alert(JSON.stringify(collection));
<!DOCTYPE html> <html> <body> <table style="width:100%" id='sport'> <thead> <tr> <td>first name</td> <td>last name</td> <td>sport</td> </tr> </thead> <tr> <td>Bob</td> <td>Smith</td> <td>football</td> </tr> <tr> <td>Dan</td> <td>Jackson</td> <td>cricket</td> </tr> <tr> <td>Will</td> <td>Rie</td> <td>Tennis</td> </tr> <tr> <td>Tom</td> <td>Lawrence</td> <td>Tennis</td> </tr> <tr> <td>John</td> <td>croft</td> <td>football</td> </tr> </table>
未經測試:嘗試在運動名稱之前添加標簽<td>
中的任何字符,例如
<td>~Baseball</td>
<td>~Football</td>
<td>~Basketball</td>
並添加一個if語句來檢查哪個td中有一個〜,並在標記中獲取文本
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