[英]MySQL select where $id
我有一個帶有此代碼段的網站:
<?php
mysql_connect('localhost','root','password');
mysql_select_db('news');
$id_article = $_GET['newsid'];
$query = mysql_query('SELECT * FROM news WHERE id="$id_article"');
{
echo '<div class="item"><h1><a href="read-news.php?newsid='.$query['id'].'">'.$query['subject'].'</a></h1><br />';
echo $query['full_content'].'<br / >';
echo date('D-M-Y', $query['date']).'<br / >';
echo 'Posted by '.$id_article;
echo '</div>';
}
?>
$id_article
從上一個請求獲取ID。 $id_article
有效,但$query
無效。 $query['***']
仍為空白。 我不知道為什么 請幫我! 非常感謝!
這樣使用
$result = mysql_query($query) or die(mysql_error());
$row = mysql_fetch_array($result) or die(mysql_error());
echo $row['id']. " - ". $row['date'];
您沒有得到查詢結果。 用法如下:
<?php
mysql_connect('localhost','root','password');
mysql_select_db('news');
$id_article = intval($_GET['newsid']);
$query = mysql_query('SELECT * FROM news WHERE id=' . $id_article);
if (mysql_num_rows($query) > 0)
{
$row = mysql_fetch_assoc($query);
echo '<div class="item"><h1><a href="read-news.php?newsid='.$row['id'].'">'.$row['subject'].'</a></h1><br />';
echo $row['full_content'].'<br / >';
echo date('D-M-Y', $row['date']).'<br / >';
echo 'Posted by '.$id_article;
echo '</div>';
}
?>
提示:使用PDO或mysqli代替mysql_函數! 不推薦使用Mysql_函數/在新的php版本中不支持!
此外,在傳遞給查詢之前,請先清理輸入內容!
您尚未使用mysql_fetch_assoc
。 用途如下:
$query = mysql_query('SELECT * FROM news WHERE id=' . $id_article);
$row = mysql_fetch_assoc($query);
if(count($row)>0)
{
echo '<div class="item"><h1><a href="read-news.php?newsid='.$query['id'].'">'.$row['subject'].'</a></h1><br />';
echo $row['full_content'].'<br / >';
echo date('D-M-Y', $row['date']).'<br / >';
echo 'Posted by '.$id_article;
echo '</div>';
}
更改您的此代碼
$query = mysql_query('SELECT * FROM news WHERE id="$id_article"');
{
echo '<div class="item"><h1><a href="read-news.php?newsid='.$query['id'].'">'.$query['subject'].'</a></h1><br />';
echo $query['full_content'].'<br / >';
echo date('D-M-Y', $query['date']).'<br / >';
echo 'Posted by '.$id_article;
echo '</div>';
}
至
$sql = "SELECT * FROM news WHERE id = $id_article";
$query = mysql_query($sql);
while($result = mysql_fetch_assoc($query));
{
echo '<div class="item"><h1><a href="read-news.php?newsid='.$result['id'].'">'.$result['subject'].'</a></h1><br />';
echo $result['full_content'].'<br / >';
echo date('D-M-Y', $result['date']).'<br / >';
echo 'Posted by '.$id_article;
echo '</div>';
}
您的代碼中有很多錯誤mysql_query已被棄用使用以下代碼並確認錯誤
<?php
mysql_connect('localhost', 'root', 'password');
$conn = mysql_select_db('news');
$id_article = $_GET['newsid'];
if($query = mysqli_fetch_assoc(mysqli_query($conn,"SELECT * FROM news WHERE id=$id_article"))){
echo '<div class="item"><h1><a href="read-news.php?newsid=' . $query['id'] . '">' . $query['subject'] . '</a></h1><br />';
echo $query['full_content'] . '<br / >';
echo date('D-M-Y', $query['date']) . '<br / >';
echo 'Posted by ' . $id_article;
echo '</div>';
}
?>
嘗試這個..
$id_article = $_GET['newsid'];
$query = "SELECT * FROM news WHERE id='$id_article'";
$query1=mysql_query($query);
您應該調用一個函數來獲取查詢返回的行。 您正在嘗試訪問$ query而不是行。 您的代碼應如下所示:
<?php
mysql_connect('localhost','root','password');
mysql_select_db('news');
$id_article = $_GET['newsid'];
$query = mysql_query('SELECT * FROM news WHERE id="$id_article"');
if ($query) {
$row = mysql_fetch_assoc($query));
echo '<div class="item"><h1><a href="read-news.php?newsid='. $row['id'].'">'. $row['subject'].'</a></h1><br />';
echo $row['full_content'].'<br / >';
echo date('D-M-Y', $row['date']).'<br / >';
echo 'Posted by '.$id_article;
echo '</div>';
} else {
$message = 'Invalid query: ' . mysql_error() . "\n";
$message .= 'Whole query: ' . $query;
die($message);
}
?>
您還可以查看mysql_result(),mysql_fetch_array(),mysql_fetch_row()函數。
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