Neo4j Java中的Cypher match（）。 查找連接的節點

Question

我有下面的結構

        firstNode = graphDb.createNode();
        firstNode.setProperty( "person", "Andy " ); 
        Label myLabel = DynamicLabel.label("A");
        firstNode.addLabel(myLabel);
        secondNode = graphDb.createNode();
        secondNode.setProperty( "person", "Bobby" );
        Label myLabel1 = DynamicLabel.label("B");
        secondNode.addLabel(myLabel1);
        ThirdNode = graphDb.createNode();
        ThirdNode.setProperty( "person", "Chris " );
        Label myLabel2 = DynamicLabel.label("C");
        ThirdNode.addLabel(myLabel2);....

        relationship = firstNode.createRelationshipTo( secondNode, RelTypes.emails );
        relationship.setProperty( "relationship", "email " );
        relationship = firstNode.createRelationshipTo( ThirdNode, RelTypes.emails );
        relationship.setProperty( "relationship", "email " );
        relationship = secondNode.createRelationshipTo( ThirdNode, RelTypes.emails );
        relationship.setProperty( "relationship", "email " );
        relationship = secondNode.createRelationshipTo( FourthNode, RelTypes.emails );
        relationship.setProperty( "relationship", "email " );

firstNode通過關系“電子郵件”鏈接到第二和第三。 類似地，第二節點連接到第三，第四，第一。

我想為每個節點輸出類似這樣的內容：secondNode = [firstNode，FouthNode，ThirdNode]，firstNode = [second，third]，third = ...

我嘗試過這樣的事情：

try{
        ExecutionEngine engine = new ExecutionEngine(graphDb);
        ExecutionResult result = engine.execute("MATCH (secondNode{person:'Bobby'})<-[:emails]-(node)RETURN node");

        System.out.println(result.dumpToString());
        tx1.success();
    } 

我得到的輸出是： Node[0]{person:"Andy "}

我對cypher很陌生。 如何為此編寫匹配語句？ 這可能嗎？

Answer 1

• 您的標簽應類似於：Person而不是：A，：B，：C
• 您想按第一個節點進行聚合。
• 您應該使用大寫重新輸入

嘗試這樣的事情：

MATCH (sender:Person)-[:EMAILS]->(receiver) 
RETURN sender,collect(receiver) as receivers