[英]create VIEW in mysql from two tables
我的郵件服務器的用戶列表。 此表用於dovecot中的imap身份驗證:
+-------------+------------------+-------------------+------------------+------+------+---------------------------------------+--------+---------+---------------------------+
| user_name | domain_name | passwd | pwd_hash | uid | gid | mailbox_basepath | enable | quota | desc_rec |
+-------------+------------------+-------------------+------------------+------+------+---------------------------------------+--------+---------+---------------------------+
| logistic | piduna.pp.ua | loG-1990M | _no_hash_passwd_ | 2000 | 2000 | /home/maildir/piduna.pp.ua/ | 1 | 2048000 | box for logistic |
| 1c | piduna.pp.ua | 1c_user_1c | _no_hash_passwd_ | 2000 | 2000 | /home/maildir/piduna.pp.ua | 1 | 2048000 | Denisyuk V.V. |
| admin | piduna.pp.ua | AAddMmM1N | _no_hash_passwd_ | 2000 | 2000 | /home/maildir/piduna.pp.ua | 1 | 2048000 | Admin |
| al.service | piduna.pp.ua | Alumo_Serv4321 | _no_hash_passwd_ | 2000 | 2000 | /home/maildir/piduna.pp.ua | 1 | 2048000 | Alumo Service |
我需要創建具有兩列的表。 第一欄,all @ piduna.pp.ua。 第二列是我所有的電子郵件帳戶。 在一張表中,我知道如何從user_name和domain_name進行串聯。 看:
CREATE VIEW `forwardings_all_view` AS select lcase(concat(`users`.`user_name`,'@',`users`.`domain_name`)) AS `email_fqn` from `users` where (`users`.`enable` = 1)
但是,如何在VIEW中添加第二列:all@piduna.pp.ua。
像那樣:
+------------------------------+-------------------------------------------------+
| email_fqn | source |
+------------------------------+-------------------------------------------------+
| .logistic@piduna.pp.ua | all@piduna.pp.ua |
| 1c@piduna.pp.ua | |
| admin@piduna.pp.ua | |
| al.service@piduna.pp.ua | |
嘗試這個:
create view first_user as
select user_name from users where enable limit 1;
create view forwardings_all_view as
select lcase(concat(a.`user_name`,'@',a.`domain_name`)) AS `email_fqn`,
if(b.user_name is null, '', 'all@piduna.pp.ua') `source`
from `users` a
left join first_user b on a.user_name = b.user_name
where a.`enable` = 1;
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