[英]php MYSQL query “ORDER BY” not working
預警:我確定我的代碼笨拙且效率低下,請隨時致電我。 我對此很陌生。
我試圖按查詢列的順序對查詢結果進行排序,該列表示為選擇輸入的結果。 select輸入存在於feed.php上 ,其功能include: 'feedphp2.php
。
選擇輸入將使用action="feedSort.php"
自動提交onchange 。 feedSort.php接收提交的值,然后重定向到feed.php?sort=submittedValue
。 然后, feed.php中包含的feedphp2.php采用$_GET['sort']
值並提取按該列排序的查詢。
//feed.php
<?php
session_start();
if(!isset($_SESSION['userID'])) {
header('Location: login.html');
}
?>
<html>
<head>
<title>Title</title>
<link href="style.css" type="text/css" rel="stylesheet">
<link href='https://fonts.googleapis.com/css
family=Josefin+Sans:400,100,300,600,700' rel='stylesheet' type='text/css'>
</head>
<body style="background-color:rgba(0,212,242,0.1)">
<div class="headerSmall">
<div class="container">
<a href="index.php"><img class="logoImgSmall"
src="images/logosmall2.png"></a>
<div class="navFeed">
<?php include 'usernameGet.php';?>,<a
href="sessionDestroy.php">Log Out</a>
<a href="addMeal.php">List a Meal</a>
<a href="dashboardBought.php">Dashboard</a>
</div>
</div>
</div>
<div class="container">
<div class="sort">
<form action="feedSort.php" method="POST">
<select name="sortForm" onchange="this.form.submit()">
<option value="">Sort By...</option>
<option value="user">By User</option>
<option value="dateAdded">By Date Added</option>
</select>
</form>
</div>
<?php include 'feedphp2.php'?>
</div>
</body>
</html>
空間
//feedphp2.php
<?php
include 'MysqlConnect.php';
mysqli_select_db($conn,$dbname);
if (isset($_GET['sort'])) {
$sortBy = $_GET['sort'];
echo $sortBy;
$resultQuery = "SELECT * FROM meals
ORDER BY '$sortBy'";
} else {
echo 'sortBy is not set.';
$resultQuery = "SELECT * FROM meals
ORDER BY user";
}
$result = mysqli_query($conn, $resultQuery);
//Write to divs
while ($rows = mysqli_fetch_assoc($result)) {
$imgSrc = $rows['image'];
echo '<a href="meal.php?'.'mealID=';
echo $rows['ID'];
echo '">';
echo '<div class="entry">';
echo '<div class="foodPic">';
echo '<img src="';
echo $imgSrc;
echo '">';
echo '</div>';
echo '<p class="entryName">'.$rows['mealName'].'</p>';
echo '<p class="entryServ">'.$rows['mealQuan'].'</p>';
echo '<p
class="entryPrice">$'.$rows['mealDollars'].'.'.$rows['mealCents'].'</p>';
echo '<img class="servingsIco" src="images/servings.png">';
echo '<p class="user">'.$rows['user'].'</p>';
echo '</div>';
echo '</a>';
}
?>
空格//feedSort.php:
<?php
session_start();
$sortBy = $_POST['sortForm'];
header ("Location: feed.php?sort=".$sortBy."");
?>
我的表中的列對於user
和dateAdded
都存在,並且在查詢中顯式提供時可以完美地排序,即: SELECT * FROM meals ORDER BY user
。 盡管通過PHP變量提供:
其中$sortBy = user
返回與$sortBy = dateAdded
完全相同的排序順序。
感謝您提供的任何幫助。
您使用$ _POST方法傳遞值,並使用$ _GET方法檢索值。 並更改不帶引號的$ sortby。 在feedphp2.php中編輯這些行
<?php
include 'MysqlConnect.php';
mysqli_select_db($conn,$dbname);
if (isset($_POST['sort'])) {
$sortBy = $_POST['sort'];
echo $sortBy;
$resultQuery = "SELECT * FROM meals
ORDER BY $sortBy";
} else {
或使用$ _REQUEST [],Method將同時獲取get和post方法
<?php
include 'MysqlConnect.php';
mysqli_select_db($conn,$dbname);
if (isset($_REQUEST['sort'])) {//request method
$sortBy = $_REQUEST['sort'];//
echo $sortBy;
$resultQuery = "SELECT * FROM meals
ORDER BY $sortBy";
} else {
聲明:本站的技術帖子網頁,遵循CC BY-SA 4.0協議,如果您需要轉載,請注明本站網址或者原文地址。任何問題請咨詢:yoyou2525@163.com.