Laravel 5雄辯地從第二個聯接表的外鍵包含另一個表的行

Question

我有3個樣本模型

1. 顧客

   ID

2. 訂購

   ID

   顧客ID

   deliver_address_id

3. customer_address

   id客戶ID

   街

   國家

客戶可以在其個人資料上保存許多地址，但每個訂單只能選擇一個地址。

我想使用laravel 5雄辯地獲得所有客戶訂單，包括一次查詢中的地址。 我是laravel的新手，因此難以查詢復雜的關系表。

Answer 1

class Customer extends Model {

    $table = 'customers';

    function addresses(){
        return $this->hasMany(Address::class, 'customer_id');
    }

    function orders(){
        return $this->hasMany(Order::class, 'customer_id');
    }

}

class Order extends Model {

    $table = 'orders';

    function address(){
        return $this->belongsTo(Address::class, 'address_id');
    }

    function customer() {
        return $this->belongsTo(Customer::class, 'customer_id');
    }
}

class Address extends Model{

    $table = 'customer_addresses';

    function customer(){
        return $this->belongsTo(Customer::class, 'customer_id');
    }

}


TABLES : 
1 customers

        id

2 orders

        id

        customer_id

        address_id

3 customer_addresses

        id

        customer_id

        street

        country