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[英]Ajax post request only prints if there are more than one echo statement
[英]How to echo only one post from a jsonfile
我已經制作了一個模塊,可以顯示instagram個人資料中的最新圖像,並且它在Joomla 3.4.8中具有一個小的彈出畫廊,非常適合我要添加個人資料圖像-profile_picture,但是當然它應該只出現一次。 我嘗試了各種php echo-但沒有運氣
有人可以幫忙嗎?
的PHP
<?php
// Supply a user id and an access token
$userid = $params->get('klintweb_insta_id');
$accessToken = $params->get('klintweb_insta_access_token');
$count = $params->get('klintweb_insta_count');
// Gets post and image
function fetchData($url){
$ch = curl_init();
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_TIMEOUT, 20);
$result = curl_exec($ch);
curl_close($ch);
return $result;
}
// Pulls and parses data.
$result = fetchData("https://api.instagram.com/v1/users/{$userid}/media/recent/?count={$count}&access_token={$accessToken}");
$result = json_decode($result);
?>
的foreach
<?php foreach ($result->data as $post): ?>
{emailcloak=off}
<!-- Renders images. @Options (thumbnail,low_resoulution, high_resolution) -->
<span class="KlintWebInstaSpan">
<a data-mediabox-group="insta" type="image/jpeg" class="jcepopup noicon" data-mediabox-caption="<?= rtrim(strip_tags(substr ($post->caption->text,0,140))).'...'; ?>" data-mediabox-title="rasmusjorgensen128" href="<?= $post->images->standard_resolution->url ?>">
<img src="<?= $post->images->thumbnail->url ?>" alt="Billede fra instagram" />
<span class="overlay"></span>
</a>
</span>
<?php endforeach ?>
json文件
{
"data": [{
"comments": {
"count": 0
},
"caption": {
"created_time": "1296710352",
"text": "Inside le truc #foodtruck",
"from": {
"username": "kevin",
"full_name": "Kevin Systrom",
"type": "user",
"id": "3"
},
"id": "26621408"
},
"likes": {
"count": 15
},
"link": "http://instagr.am/p/BWrVZ/",
"user": {
"username": "kevin",
"profile_picture": "http://distillery.s3.amazonaws.com/profiles/profile_3_75sq_1295574122.jpg",
"id": "3"
},
"created_time": "1296710327",
"images": {
"low_resolution": {
"url": "http://distillery.s3.amazonaws.com/media/2011/02/02/6ea7baea55774c5e81e7e3e1f6e791a7_6.jpg",
"width": 306,
"height": 306
},
"thumbnail": {
"url": "http://distillery.s3.amazonaws.com/media/2011/02/02/6ea7baea55774c5e81e7e3e1f6e791a7_5.jpg",
"width": 150,
"height": 150
},
"standard_resolution": {
"url": "http://distillery.s3.amazonaws.com/media/2011/02/02/6ea7baea55774c5e81e7e3e1f6e791a7_7.jpg",
"width": 612,
"height": 612
}
},
"type": "image",
"users_in_photo": [],
"filter": "Earlybird",
"tags": ["foodtruck"],
"id": "22721881",
"location": {
"latitude": 37.778720183610183,
"longitude": -122.3962783813477,
"id": "520640",
"street_address": "",
"name": "Le Truc"
}
},
{
"videos": {
"low_resolution": {
"url": "http://distilleryvesper9-13.ak.instagram.com/090d06dad9cd11e2aa0912313817975d_102.mp4",
"width": 480,
"height": 480
},
"standard_resolution": {
"url": "http://distilleryvesper9-13.ak.instagram.com/090d06dad9cd11e2aa0912313817975d_101.mp4",
"width": 640,
"height": 640
},
"comments": {
"count": 2
},
"caption": null,
"likes": {
"count": 1
},
"link": "http://instagr.am/p/D/",
"created_time": "1279340983",
"images": {
"low_resolution": {
"url": "http://distilleryimage2.ak.instagram.com/11f75f1cd9cc11e2a0fd22000aa8039a_6.jpg",
"width": 306,
"height": 306
},
"thumbnail": {
"url": "http://distilleryimage2.ak.instagram.com/11f75f1cd9cc11e2a0fd22000aa8039a_5.jpg",
"width": 150,
"height": 150
},
"standard_resolution": {
"url": "http://distilleryimage2.ak.instagram.com/11f75f1cd9cc11e2a0fd22000aa8039a_7.jpg",
"width": 612,
"height": 612
}
},
"type": "video",
"users_in_photo": null,
"filter": "Vesper",
"tags": [],
"id": "363839373298",
"user": {
"username": "kevin",
"full_name": "Kevin S",
"profile_picture": "http://distillery.s3.amazonaws.com/profiles/profile_3_75sq_1295574122.jpg",
"id": "3"
},
"location": null
},
]}
多虧了亞當·泰勒(Adam Taylor),您指出了可以做到的簡單
也感謝Danoweb的幫助
我是否正確理解您正在瀏覽一張照片列表,並且還想訪問個人資料圖片並將其打印一次?
您是否需要瀏覽所有照片? 如果沒有,您可以在打印照片后添加一個break
,以退出循環。
如果還需要遍歷照片,為什么不訪問JSON中的第一個元素,從那里獲取個人資料照片,然后遍歷其余照片?
編輯:關於您的解決方案,直接訪問第一張照片,打印相關的用戶縮略圖,然后繼續循環打印所有照片,可能會更容易。 就像是:
<div class="user">
<?php $post = $result->data[0]; ?>
<img src="<?= $post->user->profile_picture ?>" alt="<?= $post->user->username ?>" />
<span class="username"><?= $post->user->username ?></span>
</div>
<!-- do the rest of your looping/displaying photos -->
在您的解決方案中,您將數組切成一個元素,然后在您真正想要做的就是訪問第一個元素時遍歷數組。
據我了解,它似乎在JSON響應中兩次提供了個人資料圖片。 我將使用一個變量來跟蹤我是否已經顯示個人資料圖片,如果是,則不顯示第二張圖片。 例如:
<?php
$shown_profile = false;
foreach ($result->data as $post)
{
//WE HAVE NOT SHOWN PROFILE PIC, SHOW IT AND SET FLAG.
if($shown_profile == false and (image is profile pic) )
{
$shown_profile = true;
}
//WE HAVE ALREADY SHOWN PROFILE PIC AND THIS IMAGE IS A DUPLICATE
if($shown_profile == true and (image is profile pic) )
{
//JUMP TO THE NEXT LOOP INTERATION
continue;
}
//[THE REST OF YOUR FOREACH CODE]
}
?>
您可以在此處找到有關“ continue”語句的更多信息:
http://php.net/manual/en/control-structures.continue.php
希望這可以幫助!
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