僅當滿足條件時，WHERE子句中的Oracle SQL CASE表達式

Question

無法想象這一個，我有一套條件，只有當一個值在一個字段中時我才能滿足。

因此，如果狀態完成，我希望有三個where子句，如果狀態不等於完成，那么我不想要任何where子句。

碼

SELECT *
FROM mytable
WHERE CASE WHEN Status = 'Complete'
           THEN (included = 0 OR excluded = 0 OR number IS NOT NULL)
           ELSE *Do nothing*

Answer 1

通常在WHERE只使用布爾表達式很簡單。 所以：

WHERE (Status <> 'Complete') OR 
      (included = 0 OR excluded = 0 OR number IS NOT NULL)

如果Status可能為NULL ：

WHERE (Status <> 'Complete' OR Status IS NULL) OR 
      (included = 0 OR excluded = 0 OR number IS NOT NULL)

Answer 2

您可以在SQL中翻譯自然語言，然后，如果可能，重新制定。

SELECT *
FROM mytable
WHERE (Status = 'Complete' and (included = 0 OR excluded = 0 OR number IS NOT NULL)) 
     or status <> 'Complete'
     or status IS NULL;

Answer 3

它看起來不像你真的需要一個CASE語句，只需像這樣使用它：

SELECT *
FROM mytable
WHERE where (Status = 'Complete' and (included = 0 OR excluded = 0 OR number IS NOT NULL)) or (*Your do nothing*)