[英]comparison in SELECT isn't working
由於某種原因,以下代碼(用於檢查條目是否已存在):
$query = "SELECT 1 FROM Song WHERE EXISTS(SELECT *
FROM Song WHERE SongTitle = '$songtitle'
AND Duration = '$duration' AND Popularity = '$popularity'
AND Description = '$description')";
$result = pg_query($conn,$query) or die("Query could not be executed");
$row = pg_fetch_row($result);
無法正常工作,因為它在數據不同的情況下找到了一對。 這是專門針對第五首歌(Dance V)發生的。 我已經做了很多測試,但我還不能弄清楚。 任何提示將非常有幫助。
txt樣本:
TITLE | ALBUM | ARTIST | DURATION | POPULARITY | DESCRIPTION
Dance I|Glass: Dance (Nos. 1-5)|Philip Glass|19:19|16|https://api.spotify.com/v1/tracks/4v2lPpMv4OXnYWc7Oed9Ax
Dance II|Glass: Dance (Nos. 1-5)|Philip Glass|22:58|10|https://api.spotify.com/v1/tracks/5aVwAZIBbO7OuUwzsXxnQT
Dance III|Glass: Dance (Nos. 1-5)|Philip Glass|18:35|11|https://api.spotify.com/v1/tracks/2rScuezUeKzAjeCqrBe0ZY
Dance IV|Glass: Dance (Nos. 1-5)|Philip Glass|23:31|8|https://api.spotify.com/v1/tracks/515LeLoiveW3VsoLzs3eln
Dance V|Glass: Dance (Nos. 1-5)|Philip Glass|20:14|9|https://api.spotify.com/v1/tracks/77xQaN6fCsy3ZRp1eBbyXq
Dance I|Glass: Dance (Nos. 1-5)|Philip Glass|19:19|0|https://api.spotify.com/v1/tracks/77YpPPHxnqi9VaetU7OXyA
Dance II|Glass: Dance (Nos. 1-5)|Philip Glass|22:58|0|https://api.spotify.com/v1/tracks/7veCJpGBXiwjf4nYF3MIBt
Dance III|Glass: Dance (Nos. 1-5)|Philip Glass|18:35|0|https://api.spotify.com/v1/tracks/766rgBXNJmlpNLNyObbPa6
Dance IV|Glass: Dance (Nos. 1-5)|Philip Glass|23:31|0|https://api.spotify.com/v1/tracks/3xhfqJfBT60JMHzxdijMIL
Dance V|Glass: Dance (Nos. 1-5)|Philip Glass|20:14|0|https://api.spotify.com/v1/tracks/2kKz8qwXIyvV9uZD2BnTjz
表格歌曲信息:
CREATE TABLE song(
id SERIAL PRIMARY KEY,
songtitle varchar(100),
duration varchar(10),
popularity smallint,
description varchar(100)
);
碼:
while(!feof($myfile)) {
$line = fgets($myfile);
$token = strtok($line,"|");
if(feof($myfile)) break; # extra
while($token!=false) {
$word_count++;
if($word_count==1) {
$songtitle = pg_escape_string($token);
} else if($word_count==2) {
$album = pg_escape_string($token);
} else if($word_count==3) {
$artist = $token;
} else if($word_count==4) {
$duration = $token;
} else if($word_count==5) {
$popularity = $token;
} else {
$description = $token;
}
$token = strtok("|");
}
$word_count=0;
$query = "SELECT 1 FROM Song WHERE EXISTS(SELECT *
FROM Song WHERE SongTitle = '$songtitle'
AND Duration = '$duration' AND Popularity = '$popularity'
AND Description = '$description')";
$result = pg_query($conn,$query) or die("Query could not be executed");
$row = pg_fetch_row($result);
if($row[0])
{
printf("\n");
echo 'Entry already exists: ';
printf("\n");
echo 'songtitle: ';
echo $songtitle;
printf("\n");
echo 'Description: ';
echo $description;
printf("\n");
}
else
{
$query = "INSERT INTO Song (songtitle, duration, popularity, description) VALUES ('$songtitle','$duration','$popularity','$description')";
$result = pg_query($conn,$query) or die("Query could not be executed");
}
}
輸出:
postgres@user-ThinkCentre-A55:/var/www/html/songtest$ php -q add.php
Entry already exists:
songtitle: Dance V
Description: https://api.spotify.com/v1/tracks/77xQaN6fCsy3ZRp1eBbyXq
postgres@user-ThinkCentre-A55:/var/www/html/foodtest$
這可能應該是評論,但是為什么使用存在呢?
$query = "SELECT top 1 *
FROM Song WHERE SongTitle = '$songtitle'
AND Duration = '$duration' AND Popularity = '$popularity'
AND Description = '$description'";
如果僅一行,則使用top 1。
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