將MYSQLI查詢結果寫入php中的文本文件
[英]Writing MYSQLI query results to a text file in php
問題描述
<body>
<?php
ini_set('display_errors', 1);
ini_set('display_startup_errors', 1);
error_reporting(E_ALL);
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "random";
// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
$sql = "SELECT Channel_Location, Product, Active FROM channels
ORDER BY RAND()
Limit 5";
$result = mysqli_query($conn, $sql);
if (mysqli_num_rows($result) > 0) {
// output data of each row
while($row = mysqli_fetch_assoc($result)) {
$Channel_Location = $row['Channel_Location'];
echo "<tr><br><td>".$Channel_Location."</td></tr>";
}
} else {
echo "0 results";
}
$myfile = fopen("Log.txt", "w") or die("Unable to open file!");
$txt = "$result";
fwrite($myfile, $txt);
fclose($myfile);
mysqli_close($conn);
?>
</body>
所以基本上我的問題是我試圖將$result的輸出寫入文本文件，但是出現以下錯誤
該文本文件應具有5行文本，如果我更改$txt = "$Channel_Location"我將得到一個結果，但不是全部5
4 個解決方案
解決方案1
0 2016-01-21 11:34:24
您必須先連接數據，然后才能將字符串寫入文件。
$text = '';
while ($row = mysqli_fetch_assoc($result)) {
$Channel_Location = $row['Channel_Location'];
$text = $text . $Channel_Location . "\n";
}
然后，您可以執行以下操作：
fwrite($myfile, $text);
解決方案2
0 已采納 2016-01-21 11:35:07
$output = '';
$outputArray=[];
while($row = mysqli_fetch_assoc($result)) {
$Channel_Location = $row['Channel_Location'];
echo "<tr><br><td>".$Channel_Location."</td></tr>";
$output .= $row['Channel_Location']."\n";
$outputArray[] = $row;
}
file_put_contents('Log.txt',$output);
// or you can use json_encode to save whole query result!!
file_put_contents('log.txt',json_encode($outputArray));
解決方案3
0 2016-01-21 11:39:53
fwrite將字符串寫入文檔。
$result是一個對象，因此不能寫為字符串。
最好的選擇是在循環中打印出值時，也將它們添加到字符串中。
我還建議您在if語句中執行fwrite函數，因為您將需要向其寫入值，否則它將只打開文件，寫入一個空變量然后關閉。
<?php
ini_set('display_errors', 1);
ini_set('display_startup_errors', 1);
error_reporting(E_ALL);
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "random";
// Create connection
$conn = mysqli_connect($servername, $username, $password, $dbname);
// Check connection
if (!$conn) {
die("Connection failed: " . mysqli_connect_error());
}
$sql = "SELECT Channel_Location, Product, Active FROM channels
ORDER BY RAND()
Limit 5";
$result = mysqli_query($conn, $sql);
if (mysqli_num_rows($result) > 0) {
$output = '';
// output data of each row
while($row = mysqli_fetch_assoc($result)) {
$Channel_Location = $row['Channel_Location'];
echo "<tr><br><td>".$Channel_Location."</td></tr>";
$output .= $Channel_Location . '/n';
}
$myfile = fopen("Log.txt", "w") or die("Unable to open file!");
$txt = "$output";
fwrite($myfile, $txt);
fclose($myfile);
} else {
echo "0 results";
}
mysqli_close($conn);
?>
解決方案4
0 2016-01-21 11:40:27
假設您要記錄用戶
$output ='';
if (mysqli_num_rows($result) > 0) {
// output data of each row
while($row = mysqli_fetch_assoc($result)) {
$Channel_Location = $row['Channel_Location'];
$output .="<tr><br><td>".$Channel_Location."</td></tr>";
}
} else {
$output .= "0 results";
}
$myfile = fopen("Log.txt", "w") or die("Unable to open file!");
fwrite($myfile,$output);
fclose($myfile);
mysqli_close($conn);
用PHP將數據庫查詢結果寫入文本文件
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