[英]JSON VS simple string manipulation to parse HttpRequest in Android
[英]parse simple json string in android
我想使用json創建登錄和注冊系統。 我想首先獲取url的內容,然后解析json字符串。 Json String示例:
{ "employee":{"mesg":"username is exsist!","id":0,"name":0,"username":0,"email":0,"status":500} }
我只需要消息或狀態。 我無法解析它。 每次我想解析此字符串時,我的應用程序都會強制停止
這是我的代碼:
package com.sourcey.materiallogindemo;
import android.app.ProgressDialog;
import android.os.Bundle;
import android.support.v7.app.AppCompatActivity;
import android.util.Log;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;
import android.widget.TextView;
import android.widget.Toast;
import butterknife.Bind;
import butterknife.ButterKnife;
public class SignupActivity extends AppCompatActivity {
//URL to get JSON Array
//JSON Node Names
public String nurl;
private static final String TAG = "SignupActivity";
@Bind(R.id.input_name) EditText _nameText;
@Bind(R.id.input_email) EditText _emailText;
@Bind(R.id.input_tell) EditText _tellText;
@Bind(R.id.input_password) EditText _passwordText;
@Bind(R.id.btn_signup) Button _signupButton;
@Bind(R.id.link_login) TextView _loginLink;
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.activity_signup);
ButterKnife.bind(this);
_signupButton.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
signup();
}
});
_loginLink.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
// Finish the registration screen and return to the Login activity
finish();
}
});
}
public void signup() {
Log.d(TAG, "Signup");
if (!validate()) {
onSignupFailed();
return;
}
_signupButton.setEnabled(false);
final ProgressDialog progressDialog = new ProgressDialog(SignupActivity.this,
R.style.AppTheme_Dark_Dialog);
progressDialog.setIndeterminate(true);
progressDialog.setMessage("در حال انجام عملیات...");
progressDialog.show();
String name = _nameText.getText().toString();
String email = _emailText.getText().toString();
String tell = _tellText.getText().toString();
String password = _passwordText.getText().toString();
// TODO: Implement your own signup logic here.
nurl = "http://someurl/json/user.php?type=register&mobile="+tell+"&p="+password+"&email="+email+"&name="+name;
//new JSONParse().execute();
new android.os.Handler().postDelayed(
new Runnable() {
public void run() {
onSignupSuccess();
progressDialog.dismiss();
}
}, 3000);
}
public void onSignupSuccess() {
_signupButton.setEnabled(true);
setResult(RESULT_OK, null);
finish();
}
public void onSignupFailed() {
Toast.makeText(getBaseContext(), "Login failed", Toast.LENGTH_LONG).show();
_signupButton.setEnabled(true);
}
public boolean validate() {
boolean valid = true;
String name = _nameText.getText().toString();
String email = _emailText.getText().toString();
String tell = _tellText.getText().toString();
String password = _passwordText.getText().toString();
if (name.isEmpty() || name.length() < 3) {
_nameText.setError("at least 3 characters");
valid = false;
} else {
_nameText.setError(null);
}
if (email.isEmpty() || !android.util.Patterns.EMAIL_ADDRESS.matcher(email).matches()) {
_emailText.setError("enter a valid email address");
valid = false;
} else {
_emailText.setError(null);
}
if (tell.isEmpty() || !android.util.Patterns.PHONE.matcher(tell).matches()) {
_tellText.setError("enter a valid phone number");
valid = false;
} else {
_tellText.setError(null);
}
if (password.isEmpty() || password.length() < 4 || password.length() > 10) {
_passwordText.setError("between 4 and 10 alphanumeric characters");
valid = false;
} else {
_passwordText.setError(null);
}
return valid;
}
}
現在,我不知道該怎么做才能准確地解析字符串並獲取狀態或消息,謝謝您的掌舵。 我非常需要這個,抱歉提出疑問。 問候
您可以將JSONObject
用於此任務。
例如(省略try / catch):
JSONObject root = new JSONObject(jsonString);
JSONObject employee = root.getJSONObject("employee");
String message = employee.getString("name");
String username = employee.getString("username");
String email = employee.getString("email");
int id = employee.getInt("id");
int status = employee.getInt("status");
如果不確定JSON的一致性,則應首先檢查密鑰是否存在 。
您還應該檢查JSON數據類型,名稱,用戶名和電子郵件似乎包含整數。 但是,這些很少是整數。
使用Volley庫從URL獲取JSON響應,如下所示-
首先在您的項目Module:app依賴項中添加庫,如下所示-
dependencies {
compile 'com.mcxiaoke.volley:library-aar:1.0.1'
...
}
使用以下代碼從Volley Library獲得響應-
// Instantiate the RequestQueue.
RequestQueue queue = Volley.newRequestQueue(this);
String url = "WEBSERVICE_URL"; // eg:- "http://www.google.com";
// Request a string response from the provided URL.
StringRequest stringRequest = new StringRequest(Request.Method.POST, url, new Response.Listener<String>() {
@Override
public void onResponse(String response) {
System.out.println("Response is: " + response);
try {
JSONObject jobj = new JSONObject(response);
JSONObject jEmp = jobj.getJSONObject("employee");
String message = jEmp.getString("mesg");
int Status = jEmp.getInt("status");
} catch (JSONException e) {
e.printStackTrace();
}
}
}, new Response.ErrorListener() {
@Override
public void onErrorResponse(VolleyError error) {
if(error.networkResponse != null && error.networkResponse.data != null){
VolleyError verror = new VolleyError(new String(error.networkResponse.data));
System.out.println("That didn't work!\n" + error.toString());
}
}
});
// Add the request to the RequestQueue.
queue.add(stringRequest);
您可以按以下方式解析JSON-
try {
JSONObject jobj = new JSONObject(responseJSONString);
JSONObject jEmp = jobj.getJSONObject("employee");
String message = jEmp.getString("mesg");
int Status = jEmp.getInt("status");
} catch (JSONException e) {
e.printStackTrace();
}
`responseJSONString` is the JSON response you got.
建議您選擇Volley。 下面是相同的示例代碼
JsonObjectRequest jsonObjReqfirst = new JsonObjectRequest(Request.Method.GET,urlBuffer.toString(),null,
new Response.Listener<JSONObject>(){
@Override
public void onResponse(JSONObject response) {
Log.i(Constants.NETLOG, "Volley response= " + response.toString());
getResponseprocessed(response));
}
}, new Response.ErrorListener(){
@Override
public void onErrorResponse(VolleyError error) {
Log.e(Constants.NETLOG, "VolleyError response= " + error.toString());
}
});
Volley.newRequestQueue(mContext).add(jsonObjReqfirst);
void getResponseprocessed(JSONObject response){
try {
JSONObject statusObj = response.getJSONObject("employee");
String mseg=statusObj.getString("mesg");
int status = statusObj.getInt("status");
} catch (JSONException e) {
e.printStackTrace();
}
}
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