[英]creating json array in argonaut scala
我對scala,游戲框架和argonaut相當陌生。 以下是我的案例類,其中包含類型為List [Remedy]的變量。我的目標是生成PredictionModel對象的json響應,該對象包含List [Remedy]的JsonArray。
package models
import scala.collection.mutable.ListBuffer
import argonaut._, Argonaut._
/**
* Created by abhishek on 15/01/16.
*/
case class PredictionModel() {
var aboutKundali: AboutKundli = new AboutKundli()
var planetStatus = new ListBuffer[PlanetStatus].toList
var donate = ""
var notToDonate = ""
var colorNotToWear = ""
var favouredGod = ""
var aboutEducationAndOccupation = ""
var mixMahaDashaCurrent = ""
var mixMahaDashaNotCurrent = ""
var category = ""
var rinnPitri = ""
var lifeHead = ""
var disease = ""
var occupation = ""
var marriedLife = ""
var santan = ""
var parents = ""
var nature = ""
var remedyList = new ListBuffer[Remedy].toList
var importantInformation = ""
}
PredictionModel的隱式寫法是:-
implicit def predicationEncodeJson: EncodeJson[PredictionModel] =
EncodeJson((prediction: PredictionModel) =>
("about_kundali" := argonaut.Json(
"birth_rashi" := prediction.aboutKundali.birthRashi,
"lagan_rashi" := prediction.aboutKundali.laganRashi,
"birth_day_planet" := prediction.aboutKundali.birthDayPlanet,
"birth_time_planet" := prediction.aboutKundali.birthTimePlanet,
"current_maha_dasha" := prediction.aboutKundali.currentMahaDasha,
"lucky_day" := prediction.aboutKundali.luckyDay,
"lucky_number" := prediction.aboutKundali.luckyNumber
)) ->:
("important_information" := prediction.importantInformation) ->:
("rinnPitri" := prediction.rinnPitri) ->:
("category" := prediction.category) ->:
("mix_mahadasha_not_current" := prediction.mixMahaDashaNotCurrent) ->:
("mix_mahadasha_current" := prediction.mixMahaDashaCurrent) ->:
("about_education_and_occupation" := prediction.aboutEducationAndOccupation) ->:
("favored_god" := prediction.favouredGod) ->:
("color_not_to_wear" := prediction.colorNotToWear) ->:
("donate" := prediction.donate) ->:
("not_to_donate" := prediction.notToDonate) ->: jEmptyObject)
關於一切的一切都很好,但我應該怎么做才能在生產Json對象中添加JsonArray
編輯1如建議的是我的測試用例類
import argonaut._, Argonaut._
case class TestModel(id: Int, name: String) {
}
object TestModel{
implicit def PredictionModelCodecJson = CodecJson[TestModel] =
casecodec20(TestModel.apply, TestModel.unapply)("id", "name")
}
聲明casecodec20時,apply和unapply方法出錯。 我需要超越他們嗎? 還如何調用此隱式值?
編輯2
所以這是需要做的。 使用構造函數中的所有參數以及隨后的包含CodecJson的對象類創建案例類,如下所示
case class Remedy(no: Int, description: String) {
}
object Remedy{
implicit def RemedyCodecJson: CodecJson[Remedy] =
casecodec2(Remedy.apply, Remedy.unapply)("number", "description")
}
就我而言,我在模型內部擁有更復雜的模型,因此我只為所有人創建了隱式CodecJson。 如何使用它 ?
remedy.asJson
當擁有一個case類時,它會容易得多,因為您可以使用casecodec
:
implicit def PredictionModel CodecJson: CodecJson[PredictionModel] =
casecodec20(PredictionModel.apply, PredictionModel.unapply)("aboutKundali", "planetStatus", "donate", .....)
現在,您的PredictionModel
具有JSON編解碼器,它將對json中的case類進行編碼和解碼。
為了使其工作,您可以將AboutKundli
, PlanetStatus
和Remedy
定義為案例類,並以類似的方式為其創建casecodec
。
請注意,強烈建議以所有參數在其構造函數中定義的方式聲明case類,而不是在示例中顯示方式。 更好的方法是:
case class PredictionModel(
aboutKundali: AboutKundli,
planetStatus: List[PlanetStatus],
donate: String,
notToDonate: String
colorNotToWear: String
favouredGod: String,
aboutEducationAndOccupation: String,
mixMahaDashaCurrent: String,
mixMahaDashaNotCurrent: String,
category: String,
rinnPitri: String,
lifeHead: String,
disease: String,
occupation: String,
marriedLife: String,
santan: String,
parents: String,
nature: String,
remedyList: List[Remedy],
importantInformation: String)
這樣做不僅是風格上的,而且有技術上的原因(與案例類如何生成適用/不適用/平等有關),因此最好遵循這種做法。
通常,您應該遵循以下規則:case類是不可變的,並且所有值都聲明為其構造函數參數。
在為案例類聲明了編解碼器之后,就可以“免費”使用列表的編解碼器,因為Argonaut如果可以看到List[A]
可以對A
進行編碼,就可以對其進行編碼,因此您無需在此處進行任何特殊操作。
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