PHP MySQL分頁問題-其他頁面顯示所有行
[英]PHP MySQL Pagination Issue — additional pages display all rows
問題描述
我目前正在搜索數據庫，並在每頁顯示5個結果，然后打算為用戶提供指向其他頁面的鏈接。
當我運行此代碼時，它將我的初始查詢限制為5條記錄，但是當我單擊其他頁面的鏈接時，它將忽略我的sql查詢參數並重新調整數據庫中的所有行。
有誰知道為什么會這樣？
這是我的代碼：
<html>
<head>
<link rel="stylesheet" type="text/css" href="results.css">
</head>
<img src="http://meritscholarshiplist.com/wordpress/wp- content/uploads/2015/12/searchhead.png" alt="" width="100%" style="padding-top:0px;"/>
<a href="http://meritscholarshiplist.com/wordpress/search-2#searcht|0"><-Search Again</a>
</html>
<?php
require('./wp-blog-header.php');
$current_user = wp_get_current_user();
$school = $_POST['school'];
$num_rec_per_page=5;
mysql_connect('', '', '');
mysql_select_db('');
if (isset($_GET["page"])) {
$page = $_GET["page"];
} else {
$page=1;
}
;
$start_from = ($page-1) * $num_rec_per_page;
$sql = "SELECT * FROM `data` WHERE `school` LIKE '%$school%' LIMIT $start_from, $num_rec_per_page";
$rs_result = mysql_query ($sql);
//run the query
while ($array = mysql_fetch_row($rs_result)) {
echo "<div class='list' style='width:1750px; margin:0 auto;'>";
echo "<form action='singleview.php' method='post' target='_new$array[0]'><table id='scholarship' style='float:left;' align='center'><thead><th class='head' colspan='3' style='text-align:center;'>$array[2]<br><br>$array[5]<br><br>$array[3]<br><br><input type='hidden' name='id' value='$array[0]'><input type='submit' value='View More Details'><br>(Will Open in a New Tab)</th></thead>";
echo "</form></table></div> ";
}
;
?>
<?php
$school = $_POST['school'];
$sql = "SELECT * FROM `data` WHERE `school` LIKE '%$school%'";
$rs_result = mysql_query($sql);
//run the query
$total_records = mysql_num_rows($rs_result);
//count number of records
$total_pages = ceil($total_records / $num_rec_per_page);
echo "<a href='search.php?page=1'>".'|<'."</a> ";
// Goto 1st page
for ($i=1; $i<=$total_pages; $i++) {
echo "<a href='search.php?page=".$i."'>".$i."</a> ";
}
;
echo "<a href='search.php?page=$total_pages'>".'>|'."</a> ";
// Goto last page
echo "<br>Your Search Returned $total_records Results";
?>
1 個解決方案
解決方案1
1 已采納 2016-01-26 23:45:20
當您單擊頁碼時，您的瀏覽器正在發出GET請求，而沒有school的值。 您可以先將school添加到請求中，例如
echo "<a href='search.php?page=1&school=".urlencode($school)."'>".'|<'."</a> ";
// Goto 1st page
for ($i=1; $i<=$total_pages; $i++) {
echo "<a href='search.php?school=".urlencode($school)."&page=".$i."'>".$i."</a> ";
}
並確保您可以通過GET和POST獲得school的價值：
$school = $_REQUEST['school']; // instead of $_POST['school']
PHP分頁問題mysql和php在所有頁面上顯示相同的數據
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