中斷嵌套的for循環后繼續while循環

Question

在嵌套嵌套循環中滿足某些條件之后，我正在尋找一種更pythonic的方式來繼續while循環。 對我有用的非常笨拙的代碼是：

tens = ['30','40','50','60','70','80','90','00']
z=0
while z==0:
    num = input('Please enter a number: ')
    z=1    
    for x in tens:
        if num[0]=='0' or x in num:
            print('That was an invalid selection, please try again.\n')
            z=0  # There has GOT to be a better way to do this!
            break
print(num+' works, Thank You!')

我可以使用try / except來回答這個問題 ：

tens = ['30','40','50','60','70','80','90','00']
while True:
    num = input('Please enter a number: ')  
    try:
        for x in tens:
            if num[0]=='0' or x in num:
                print('That was an invalid selection, please try again.\n')
                raise StopIteration
    except:
        continue
    break
print(num+' works, Thank You!')

我面臨的挑戰是

a）在滿足if的情況下繼續while循環（請求新輸入）（換句話說，中斷for循環並在同一步驟中繼續while循環）

b）在測試每個新輸入時，從頭開始運行可迭代的十位。

注意：此問題與Reddit Challenge＃246 字母拆分有關

更新：合並了HåkenLid提供的答案，代碼變為

tens = ['30','40','50','60','70','80','90','00']
while True:
    num = input('Please enter a number: ')
    if num[0]=='0' or any(t in num for t in tens):
        print('That was an invalid selection, please try again.\n')
        continue
    break
print(num+' works, Thank You!')

我還沒有解決“從嵌套的for循環中中斷/繼續”的問題，但是用any（）函數代替循環肯定對我有用。

Answer 1

不需要您的for循環。 只需in關鍵字中使用。 但是除此之外，您可以使用break很好。

tens = ['30','40','50','60','70','80','90','00']
while True:
    num = input('Please enter a number: ')
    if num in tens:
       break
    print('That was invalid selection, please try again.\n')
print(num+' works, Thank You!')

Answer 2

在大多數情況下，具有嵌套循環是不好的設計。

您的功能應始終盡可能小。 遵循該規則，您將永遠不會違反SOLID（單一負責原則）的第一條規則。

您的代碼可能如下所示：

tens = ['30','40','50','60','70','80','90','00']

def main():
    while 1:
        num = input('Please enter a number: ')
        if nested_test(num):
            print('That was an invalid selection, please try again.\n')
            break

def nested_test(num):
    for x in tens:
        if <some test>:
            return True