如何從PHP獲取SQL中受影響的行

Question

我寫下了以下代碼。但是，當我嘗試獲取受影響的行（以檢查用戶詳細信息是否與數據庫的行匹配）時，即使語句成功執行，它也總是返回0作為受影響的行。.我做錯了什么？

if($connection){

$username = "admin";
$password = "admin";

$statement = mysqli_prepare($connection,"SELECT * FROM  `admin` WHERE username = ? AND password = ?");

mysqli_stmt_bind_param($statement,"ss",$username,$password);
mysqli_stmt_execute($statement);

if(mysqli_affected_rows($connection) == 1){
    $response = array('response'=>true);
}else{
    $response = array('response'=>false);
}

echo json_encode($response);

mysqli_stmt_close($statement);
mysqli_close($connection);     }

Answer 1

使用mysqli_stmt_affected_rows（）函數，該函數將一條語句作為參數：

更改

if(mysqli_affected_rows($connection) == 1)

至

if(mysqli_stmt_affected_rows($stmt) != 0)