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[英]pthread_atfork() called more than once causing after fork() functions to be called more than once
[英]Declaring variables in functions that are called more than once in int main() (in C)
如標題中所述,我要處理一個在main中多次調用的函數,其目的是對字符數組中的元音進行計數,並且僅在第一次調用時結果才正確。 之后,它不是從零開始,而是從中斷的地方開始計數,從而導致錯誤的結果。
這是功能:
int function(char *pointer, int num_of_elements)
{
int i=0;
if (num_of_elements==0) return i;
if ((*pointer== 'a') || (*pointer== 'A') || (*pointer== 'e') || (*pointer== 'E') || (*pointer== 'i') || (*pointer== 'I' )||( *pointer=='o') || (*pointer =='O') || (*pointer== 'u') || (*pointer== 'U')) {i++;}
pointer++;
num_of_elements--;
return function(pointer,num_of_elements);
}
指針指向字符數組,變量i為計數器。
您必須返回i
的總和以及function
的遞歸調用的結果。 像這樣修改您的代碼:
#include <ctype.h>
int function(char *pointer, int num_of_elements)
{
if (num_of_elements==0)
return 0;
char c = tolower( *pointer );
int i = ( c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u' ) ? 1 : 0;
pointer++;
num_of_elements--;
return i + function( pointer, num_of_elements );
}
我建議循環解決您的問題,並使用tolower
函數:
#include <ctype.h>
int function(char *pointer, int num_of_elements)
{
int count = 0;
for ( int i = 0; i < num_of_elements; i++, pointer ++)
{
char c = tolower( *pointer );
if ( c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u' )
count ++;
}
return count;
}
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