[英]PHP replace a character in string fetched from mysql
我正在嘗試將包含值的字符串替換為operator:例如將“ 2456:72”替換為“ 2456.72”,其中從mysql提取數據,我嘗試使用可吸收的str_replace
。 $row_loop3["Tot_minutes"]
是我應該替換字符的行,請找到我的代碼:
$mysqli = new mysqli("172.16.10.102", "******", "RND@ISO-3306", "eTrans");
if (!$mysqli->multi_query("call sp_get_Android_Online_minutes_Chart ('2015-01-01','2016-01-30')")) {
$response["success"] = 0;
}
do {
if ($res_loop3 = $mysqli->store_result()) {
$response_loop3["minutes"] = array();
$find = ":";
$re = ".";
while ($row_loop3 = $res_loop3->fetch_assoc()) {
$j = 5;
$value_loop3 = array();
$value_loop3["File_Day"] = $row_loop3["edit_date"];
$value_loop3["File_Minutes"] = $row_loop3["FileDay"];
$val["Tot1_Minutes"] = $row_loop3["Tot_minutes"];
$value_loop3["Total_Minutes"] = str_replace($val, $find, $re); //value which I should replace : with .
array_push($response_loop3["minutes"], $value_loop3);
$response_loop3["success"] = 1;
}
echo $merger = json_encode(array_merge($response, $response_loop2, $response_loop3));
$res->free();
}
} while ($mysqli->more_results() && $mysqli->next_result());
請幫助我,謝謝
您不是在創建變量,而是在創建關聯數組。 改變這個
$val["Tot1_Minutes"] = $row_loop3["Tot_minutes"];
至
$val= $row_loop3["Tot_minutes"];
並在str函數中訂購
$val = $row_loop3["Tot_minutes"];
$value_loop3["Total_Minutes"]=str_replace($find,$re,$val);
str_replace
應該以這種方式使用:
str_replace( mixed $search , mixed $replace , mixed $subject [, int &$count ] )
該函數的參數是search,replace和subject,因此對於您的情況應類似於: str_replace($find,$re,$val)
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