用 belongsToMany 關聯對 findAll 進行續集

Question

我有兩個以這種方式相關的表：

聯盟

sequelize.define('league', {
  name: {
    type: DataTypes.STRING,
  },
  ownerId: {
    type: DataTypes.INTEGER,
  }
}, {
    classMethods: {
    associate: function(models) {
      League.belongsToMany(models.user, {
        constraints: false,
        through: models.UserLeague,
      });
    }
  }
}, {
    freezeTableName: true
});

用戶

sequelize.define('user', {
  name: {
    type: DataTypes.STRING
  },
  email: {
    type: DataTypes.STRING,
    unique: true,
    validate: {
        isEmail: true
    }
  },
  profile_picture: {
    type: DataTypes.STRING
  }
}, {
    classMethods: {
    associate: function(models) {
      User.belongsToMany(models.league, {
        constraints: false,
        through: models.UserLeague,
      });
    }
  }
}, {
  freezeTableName: true
});

我想獲取所有擁有特定用戶的聯賽：我目前正在這樣做，但我收到錯誤column league.users.id does not exist

sequelize.transaction(function (t) {
    return models.user.findOne({where: {email: req.query.email}}, {transaction: t}).then(function(user) {
      return models.league.findAll({where: {'users.id': user.id}, include: [{model: models.user, as: 'users'}]}).then(function(leagues) {
        res.json(leagues);
      });
    });
});

我怎樣才能檢索有某個用戶的聯賽？

Answer 1

您應該將where添加到隨附的模型中：

sequelize.transaction(function (t) {
    return models.user.findOne({where: {email: req.query.email}}, {transaction: t}).then(function (user) {
        return models.league.findAll({
            include: [{
                model: models.user,
                as: 'users',
                where: {
                    id: user.id
                },
                required: true
            }]
        }).then(function (leagues) {
            res.json(leagues);
        });
    });
});

更新：

它不是很好，但是我認為，沒有更好的解決方案：

sequelize.transaction(function (t) {
    return models.user.findOne({where: {email: req.query.email}}, {transaction: t}).then(function (user) {
        var _leagueIds = [];
        return models.league.findAll({
            include: [{
                model: models.user,
                as: 'users',
                where: {
                    id: user.id
                },
                required: true
            }]
        })
            .each(function (league) {
                _leagueIds.push(league.id);
            })
            .then(function () {
                return models.league.findAll({
                    where: {
                        id: _leagueIds,
                    },
                    include: [{
                        model: models.user,
                        as: 'users'
                    }]
                });
            })
            .then(function (leagues) {
                res.json(leagues);
            });
    });
});

Answer 2

總結本文檔<\/a>，我們有以下內容：

如果您有以下型號：

const User = sequelize.define('user', { name: DataTypes.STRING });
const Task = sequelize.define('task', { name: DataTypes.STRING });