按空屬性/條目過濾對象

Question

我該如何過濾像這樣的對象：

{"firstname":"foo","lastname":"bar","driving":"","overnight":""}

至

{"firstname":"foo","lastname":"bar"}

僅刪除空鍵/值對

Answer 1

for (key in obj) {
    if (obj.hasOwnProperty(key) && obj[key] === '') {
        delete obj[key];
    }
}

Answer 2

使用Object.keys（）和Array.prototype.forEach（）的解決方案：

var original = {"firstname":"foo","lastname":"bar","driving":"","overnight":""};
var filtered = {}
Object.keys(original).forEach(function(key) {
    if (original[key] !== "") {
        filtered[key] = original[key];
    }
});
console.log(filtered);

Answer 3

您也可以嘗試一下。 此代碼刪除按鍵測試和駕駛

var obj = {"firstname":"foo","lastname":"bar","driving":"","overnight":"", "test": null};
Object.keys(obj).forEach(function(k) {
    if (!obj[k] || obj[k] === "") {
        delete obj[k];
    }
});
console.log(obj);