[英]CODEIGNITER: check if ingredient exist
我有表成分w / c包含(ingredient_id,name),類別w / c包含(category_id,name)和category_ingredients w / c包含(ingredient_id,category_id)。 我創建了一個用於按類別添加許多成分的表單,我想檢查是否已存在一種或多種成分,那么我只需要獲取成分的ID,然后將其他不存在的成分插入到我的數據庫中。 你們能幫我嗎?
這是我的代碼:VIEW:
<?php echo form_open('dashboard/uploadIngredients', 'class="form-horizontal" enctype="multipart/form-data"'); ?>
<div class="form-group">
<div class="col-sm-10">
<select required class="form-control" name="ingredient_category">
<option value="" selected disabled>Select Ingredient Category</option>
<option value="All">All</option>
<?php foreach($this->products_model->getCategory() as $row): ?>
<option value="<?php echo $row->category_id ?>"><?php echo $row->category_name; ?></option>
<?php endforeach; ?>
</select>
</div>
</div>
<div class="form-group">
<div class="col-sm-10">
<textarea class="form-control" name="ingredients" rows="5" placeholder="Ingredients (EX. onion, oil, pasta)" required></textarea>
</div>
</div>
<div class='form-group'>
<div class="col-sm-10">
<button class="btn btn-lg btn-positive" type="submit"><i class="glyphicon glyphicon-ok"></i> Save Ingredient</button>
</div>
</div>
<?php echo form_close(); ?>
控制器:
public function uploadIngredients()
{
foreach(explode(',', $this->input->post('ingredients')) as $key => $value)
{
$saveData[] = array('ingredient_id' => null,
'name' => trim($value)
);
}
$ingredient_id = $this->products_model->saveIngredients($saveData);
foreach (explode(',', $this->input->post('ingredient_category')) as $key => $value)
{
foreach ( $ingredient_id as $key => $str ){
$joinData[] = array(
'ingredient_id' => $str,
'category_id' => intval($value)
);
}
//var_dump($joinData); die();
$this->products_model->saveCategoryIngredients($joinData);
redirect('dashboard/add_ingredients');
}
}
模型:
public function saveIngredients($ingredient_id)
{
foreach($ingredient_id as $row => $value) {
$query=$this->db->where('ingredient_id', $value->ingredient_id);
$this->db->insert('ingredient', $value);
$insert_id[] = $this->db->insert_id();
}
return $insert_id;
}
public function saveCategoryIngredients($data)
{
foreach($data as $row => $value)
{
$this->db->insert('category_ingredient', $value);
$insert_id[] = $this->db->insert_id();
}
return $insert_id;}
}
您只需要向模型中添加一個函數,就像這樣:
<?php
public function getIngredientByName($name) {
return $this->db
->from('ingredient I')
->where('I.name', $name)
->get()->row(); //Will return the row of ingredient if ingredient exists, else null
}
在您的控制器中:
<?php
foreach(explode(',', $this->input->post('ingredients')) as $key => $value)
{
if (!$this->products_model->getIngredientByName($value)) {
$saveData[] = array(
'ingredient_id' => null,
'name' => trim($value)
);
}
}
感謝Gwendal回答了這個問題,我正在對此答案進行一些修改,以防止重復插入,例如:-如果用戶插入SuGar CaNe,但我們在數據庫中有甘蔗,那么帶有答案的代碼中我們將有2個甘蔗來避免此類插入我們可以使用此代碼進行模型
<?php
public function getIngredientByName($name) {
return $this->db
->from('ingredient I')
-> where("( REPLACE( LOWER(I.name), ' ', '') LIKE '".strtolower(preg_replace('/\s+/', '', $name)) ."%')")
->get()->row(); //Will return the row of ingredient if ingredient exists, else null
}
與控制器相同
<?php
foreach(explode(',', $this->input->post('ingredients')) as $key => $value)
{
if (!$this->products_model->getIngredientByName($value)) {
$saveData[] = array(
'ingredient_id' => null,
'name' => trim($value)
);
}
}
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