CakePHP 3錯誤：SQLSTATE [42000]：語法錯誤或訪問沖突：1064

Question

我收到此錯誤：

Error: SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'AS `Colleges__*` FROM college_admins CollegeAdmins LEFT JOIN colleges Colleges O' at line 1

這是給出此錯誤的SQL查詢：

SELECT Colleges.* AS `Colleges__*` FROM college_admins CollegeAdmins LEFT JOIN colleges Colleges ON Colleges.id = (CollegeAdmins.college_id) WHERE CollegeAdmins.user_id = :c0 LIMIT 20 OFFSET 0

我啟用了quoteIdentifiers config \\ app，但它導致了這個新錯誤：

Error: SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MariaDB server version for the right syntax to use near 'AS `Colleges__*` FROM `college_admins` `CollegeAdmins` LEFT JOIN `colleges` `Col' at line 1

查詢變為：

SELECT `Colleges`.* AS `Colleges__*` FROM `college_admins` `CollegeAdmins` LEFT JOIN `colleges` `Colleges` ON `Colleges`.`id` = (`CollegeAdmins`.`college_id`) WHERE `CollegeAdmins`.`user_id` = :c0 LIMIT 20 OFFSET 0

我認為它將'Col from Colleges'作為關鍵字'COL'，但是我不確定。 如何解決這個問題？

這是生成MySQL查詢的CakePHP代碼：

return $college_admins->find()
    ->select(['Colleges.*'])
    ->leftJoinWith('Colleges')
    ->where(['CollegeAdmins.user_id' => $userId]);

Answer 1

您不能在CakePHP ORM查詢（CakePHP 3.x）中使用Colleges.* 。 如您所知，這會創建不正確的SQL別名，例如Colleges__* 。 而是選擇一個表的所有列，您需要傳遞一個表對象。

所以您可能想要做類似的事情：-

->select($college_admins->Colleges)

假設Colleges與您的CollegeAdmins表相關聯。

Answer 2

您不能為colleges。*加上別名，因為這是指colleges表中的所有列，而別名是指單個列（或表或子查詢）。 您需要列出colleges表中的所有字段，並為每個字段提供一個別名，例如

select colleges.ig as colleges_id, colleges.field1 as colleges_field1, ...

sql中沒有語法提供這種方式的別名。 您可能想做的是訪問mysql在php中返回的元數據，以檢索每個字段的表名。