[英]How to exit a while loop in python?
我正在做這個簡單的任務,我需要使用2個while循環。 第一個while循環檢查小時數是否小於0,如果是,則循環應該繼續詢問用戶。 這是我的代碼:
hours = float(input('Enter the hours worked this week: '))
count = 0
while (0 > hours):
print ('Enter the hours worked this week: ')
count = count + 1
pay = float(input('Enter the hourly pay rate: '))
while (0 > pay):
print ('Enter the hourly pay rate: ')
count = count + 1
total_pay = hours * pay
print('Total pay: $', format(total_pay, ',.2f'))
break
是你正在尋找的。
x = 100
while(True):
if x <= 0:
break
x -= 1
print x # => 0
至於你的例子,似乎沒有任何東西會導致中斷發生。 例如:
hours = float(input('Enter the hours worked this week: '))
count = 0
while (0 > hours):
print ('Enter the hours worked this week: ')
count = count + 1
您根本沒有編輯hours
變量。 這只會繼續打印出"Enter the hours worked this week: "
和無限增量count
。 我們需要知道提供更多幫助的目標是什么。
您可以通過使用break
或使條件為false來退出循環。
在您的情況下,您從用戶處獲取輸入,如果hours < 0
,則打印提示並更新計數,但不會更新小時數。
while (0 > hours):
print ('Enter the hours worked this week: ')
count = count + 1
應該:
while (0 > hours):
hours = float(input('Enter the hours worked this week: '))
count = count + 1
同樣的薪酬:
while (0 > pay):
pay = float(input('Enter the hourly pay rate: '))
count = count + 1
好吧,另一個答案向您展示了如何突破while循環,但您也沒有分配付費和小時變量。 您可以使用內置輸入功能來獲取用戶提供給程序的內容
hours = float(input('Enter the hours worked this week: '))
count = 0
while (0 > hours):
hours = input('Enter the hours worked this week: ')
count = count + 1
pay = float(input('Enter the hourly pay rate: '))
while (0 > pay):
pay = input('Enter the hourly pay rate: ')
count = count + 1
total_pay = hours * pay
print('Total pay: $', format(total_pay, ',.2f'))
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