[英]How to display an image stored in Mysql database with special date not by id (php)
我正在嘗試顯示上傳到MySql中“上傳”表的圖像。 我已經讀了很多關於如何做到這一點的書,但是沒有運氣。
“ news_content”表用於將NEWS內容上載到Mysql,並具有6列:id,標題,描述,content_text,日期,時間
和“上傳”表有5列:ID,名稱,大小,圖像,日期
在“ news_content”表中,我分別上傳了日期和時間列,但“上載”表中的日期列是一個字符串,其中同時包含了日期和時間。 例如,如果在“ news_content”表中日期為2/3/2016,時間為5:30,則在“上載”表中日期為2/3/20165:30。 我以這種方式進行了組織,以便按相關帖子上傳的特定日期和時間來檢索圖像。
我使用以下代碼將圖像上傳到news.php頁面:
news.php:
// Create connection
$connection = mysql_connect("localhost","root","p206405az");
// Check connection
if (!$connection) {
die("Connection failed: " . mysql_error());
}
//select a database to use
$db_select = mysql_select_db( "news" , $connection) ;
if (!$db_select) { die("Selection faild:" . mysql_error()) ;
}
//uploading the content of news and date and time
if(isset($_POST["submit"])){
$title = $_POST["title"] ;
$description = $_POST["description"] ;
$content_text = $_POST["content_text"] ;
$date = $_POST["date"] ;
$time = $_POST["time"] ;
//perform mysql query
$result = mysql_query("INSERT INTO news_content (title, description, content_text, date, time)
VALUES ('$title', '$description', '$content_text' ,'$date' , '$time' )") ;
if (!$result) {
die("Insert failed: " . mysql_error());
$submitMessage = "Problem with updating the post, please try again" ;
} else if ($result){
$submitMessage = "Your post succsessfully updated" ;
}
}
// uploading the image
if(isset($_POST['submit']) && $_FILES['image']['size'] > 0)
{
$fileName = $_FILES['image']['name'];
$tmpName = $_FILES['image']['tmp_name'];
$fileSize = $_FILES['image']['size'];
$fileType = $_FILES['image']['type'];
$filedate = "$date" . "$time" ;
$fp = fopen($tmpName, 'r');
$content2 = fread($fp, filesize($tmpName));
$content3 = addslashes($content2);
fclose($fp);
if(!get_magic_quotes_gpc())
{
$fileName = addslashes($fileName);
}
$query = "INSERT INTO upload (name, size, type, image, date ) ".
"VALUES ('$fileName', '$fileSize', '$fileType', '$content3', '$filedate')";
mysql_query($query) or die('Error2, query failed');
}
我想通過getImage.php頁面檢索該圖像,以便稍后通過以下代碼將其用作源頁面,但看來它無法檢索blob數據:
PS圖像已成功上傳,但是我無法使用最近發布的特定日期進行檢索
getImage.php:
// Create connection
$connection = mysql_connect("localhost","root","p206405az");
// Check connection
if (!$connection) {
die("Connection failed: " . mysql_error());
}
//select a database to use
$db_select = mysql_select_db( "news" , $connection) ;
if (!$db_select) { die("Selection faild:" . mysql_error()) ;
}
//perform mysql query
$result = mysql_query("SELECT * FROM news_content" , $connection);
if (!$result) {
die("read failed: " . mysql_error());
}
//useing returned data
while ($content = mysql_fetch_array($result)){
$date = $content["date"];
$time = $content["time"] ;
}
$filedate = "$date" . "$time" ;
$result2 = mysql_query("SELECT image FROM upload WHERE date='$filedate'" , $connection);
if (!$result2) {
die("read failed: " . mysql_error());
};
$row = mysql_fetch_assoc($result2);
mysql_close($connection);
header("Content-type: image/jpeg");
echo $row['image'];
我想使用以下HTML代碼在index.php頁面中顯示圖像:
index.php:
<img src="getImage.php?date=<?php echo $filedate ; ?>" width="175" height="200" />
如何在getImage.php頁面中檢索該數據,然后使用該頁面和az源頁面在index.php頁面中顯示圖像? 任何幫助,將不勝感激。
除非PHP拋出錯誤,否則無法找出錯誤。 但是我會將圖像保存為文件而不是db,並在新聞表的行中保留其名稱,除非每個新聞有多個圖像。
如果每個新聞有多個圖像,我將圖像ID與新聞ID匹配。
news.db的架構
id, title, description, content_text, date, time
upload.db的模式:
id, image, newsid
我的圖片HTML鏈接應該是:
<img src="getImage.php?id=<?php echo $newsid; ?>" width="175" height="200" />
然后我的getimage.php應該是這樣的:
$connection = mysql_connect("localhost","root","p206405az");
if (!$connection) {
die("Connection failed: " . mysql_error());
}
$db_select = mysql_select_db( "images" , $connection) ;
if (!$db_select) {
die("Selection faild:" . mysql_error()) ;
}
$id=$_GET["id"];
$result = mysql_query("SELECT image FROM upload WHERE newsid='$id' LIMIT 1" , $connection);
if (!$result) {
die("read failed: " . mysql_error());
};
$row = mysql_fetch_assoc($result);
mysql_close($connection);
header("Content-type: image/jpeg");
print $row['image'];
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