如何使用它來自循環之外的變量？ 的PHP

Question

自發布以來，我已經更新了代碼。

我正在嘗試在計算出的循環之外回顯變量。

foreach ($query->result() as $row){ //loop to display all team members


   echo '<table border="1"><tr><td>User</td><td>Hours</td></tr>';

   $this->db->select('users.USER_EMAIL'); //we want to display the users' emails who are in this team.
   $this->db->from('users');
   $this->db->join('user_teams', 'users.USER_ID = user_teams.USER_ID'); //we need to join these tabels in order to get this
   $this->db->join('teams', 'teams.TEAM_ID = user_teams.TEAM_ID');
   $this->db->where('teams.TEAM_NAME', $row->TEAM_NAME); //search for the team name that we are currently looking at
   $team_query = $this->db->get();


   echo '<h2>Team: ';
   echo $row->TEAM_NAME;
   echo '</h2>';
$total = date('h:i:s', NULL);
var_dump($total); //outputs "01:00:00" as a string
foreach ($team_query->result() as $team_row) {

var_dump($total); //outputs "01:00:00" as a string


echo '<tr>';
echo '<td>';
echo $team_row->USER_EMAIL;
echo '</td>';

$this->db->select('SEC_TO_TIME( SUM( TIME_TO_SEC( `USER_WORK_HOURS` ) ) ) AS totalHours');
$this->db->where('USER_EMAIL', $team_row->USER_EMAIL);
$hours= $this->db->get('user_hours')->row()->totalHours;

echo '<td>';
echo $hours; //outputs "00:11:01" as a string, that is the correct value 
echo '</td>';
var_dump($hours); //outputs "00:11:01" as a string. still correct
$total += $hours; //im guessing the += operators do not work on time
var_dump($total); //outputs 1 as int, not correct. should be "00:11:01" as a string for the first time around the loop

echo '</tr>';
echo '<br />';
}
    echo '<tr>';
    echo '<td>';
    echo 'Total'; //outputs 1 as int
    echo '</td>';
    echo '<td>';
    echo $total; //outputs 1 as int
    echo '</td>';
    echo '</tr>';
     echo '</table>';

}    

它可能與時間格式有關嗎？

如果有的話，增加時間的正確方法是什么？

如果這很重要，我正在使用codeigniter 3x。

讓我知道是否需要其他信息。

先感謝您。

Answer 1

可能是您的查詢結果返回零行數。 確保$ team_query有結果。

result（）as $ team_row）{$ total + = $ hours; }？>

Answer 2

這是解決方案

       $hours= $this->db->get('user_hours')->row()->totalHours;

        make sure that $hours variable contains an integer value 
        or float value 
        it should not a be string and also not be empty.


You can initialize  $total = 0;  $hours=0;

Answer 3

算術加法（ +運算符）將不適用於“ 01:00:00”之類的字符串。 您必須將它們轉換為添加之前的秒數（通過TIME_TO_SEC() MySQL函數），或者按照此處的建議通過SQL計算整個值。

另外，在循環之前查看SQL是很有趣的（通過$ query檢索的SQL）：我很確定您可以一次性獲得所有需要的數據，而無需嵌套查詢和PHP計算。