獲取列的失敗百分比

Question

+------------+---------+------------+--------------+------+
| dt         | status  | code       | arena        | cnt  |
+------------+---------+------------+--------------+------+
| 2016-01-01 | failure | AB         | kingdom1     |    2 |
| 2016-01-01 | success | AB         | kingdom1     |   16 |
| 2016-01-01 | failure | CD         | kingdom1     |   50 |
| 2016-01-01 | success | CD         | kingdom1     |  662 |
| 2016-01-01 | failure | EF         | kingdom1     |  131 |
| 2016-01-01 | success | EF         | kingdom1     |  622 |

SQL查詢：

select DATE(created) as dt, status, code, arena,count(status) as cnt
from game_table
where some_condition
group by dt, code, status)

要求：

我需要找到code失敗百分比，但在arena還是不錯 ，但是我嘗試的是為所有code返回100％失敗（ baaaaad coder ）。

+------------+---------+------------+--------------+------+
| dt         | status  | code       | arena        |failed|
+------------+---------+------------+--------------+------+
| 2016-01-01 | failure | AB         | kingdom1     | 11.1 |
| 2016-01-01 | failure | CD         | kingdom1     | 7.02 |
| 2016-01-01 | failure | EF         | kingdom1     | 17.4 |

我試過了 ：

select dt, cnt/sum(cnt) as p, status, code, arena 
from (
  select DATE(created) as dt, status, code, arena,count(status) as cnt
  from game_table
  where some_condition
  group by dt, code, status
 ) as inner_t
group by dt, code, status;

Answer 1

您可以通過以下代碼獲取失敗或成功組的百分比。

 select DATE(created) as dt, count(case when status = "failure" then 1 end) * 100/count(status) as failure, code, arena, cnt
 from percent_issue group by code

Answer 2

主要問題似乎是正確理解GROUP BY。 它僅表示“每______向我顯示一個結果行”。 您似乎希望每個code一個結果行，所以您group by code 。 如果您希望每個code和arena一行，則按code arena group by code, arena 。 對於不在GROUP BY的字段，請確定要顯示的匯總，例如最短日期。

select 
  min(created)
  'failure' as status,
  code,
  min(arena) as arena,
  count(case when status = 'failure' then 1 end) / count(*) * 100 as failed
from game_table
where some_condition
group by code;