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[英]How to remove duplicates in one column based on the value of other columns in psql
[英]Add additional column in a SELECT statement based on values of other columns PSQL
我有一張每人的駕駛執照表,並且知道一個人何時獲得了駕駛執照。 駕駛執照的有效期可以是您獲得駕照之日的X天,也可以是特定日期。
acquired relative specific_date valid_type expiration_date
----------------------------------------------------------------------------------
2015-02-05 500 null days
2015-02-05 null 2016-03-05 date
2015-02-05 200 null days
2015-02-05 null 2016-02-22 date
我現在的查詢是:
SELECT acquired,
relative_date,
specific_date,
valid_type
FROM person_drivers_license
WHERE (valid_type = 'days'
AND (EXTRACT(epoch
FROM acquired) - EXTRACT(epoch
FROM now()))/86400 + relative_date > 0)
OR (valid_type = 'DATE'
AND specific_date >= now()));
我正在嘗試使用上面的select語句添加expiration_date列。 如果是特定日期,則只需輸入日期並將其放在expiration_date中;如果是相對日期,則在獲取的日期的幫助下計算到期日期。 在PSQL中這可能嗎?
嘗試這個:
SELECT acquired,
relative_date,
specific_date,
valid_type
CASE valid_type
WHEN 'days' THEN acquired + relative_date
WHEN 'date' THEN specific_date
ELSE NULL
END AS expiration_date
FROM person_drivers_license;
首先-在postgres中有一種更簡單的日期數學計算方法。 您可以使用類似:
acquired + relative_date * interval '1 day' >= current_date
要么
acquired + relative_date >= current_date
-- any integer can be treated as interval in days for date mathematics is SQL
對於問題-嘗試以下一種方法:
CASE WHEN valid_type = 'days'
THEN acquired + relative_date * interval '1 day'
WHEN valid_type = 'date'
THEN specific_date
--ELSE ??? you may specify something here
END
要么
COALESCE(specific_date, acquired + relative_date * interval '1 day')
該查詢可能類似於:
SELECT acquired,
relative_date,
specific_date,
valid_type,
COALESCE(specific_date, acquired + relative_date * interval '1 day') as valid_date
FROM person_drivers_license
WHERE COALESCE(specific_date, acquired + relative_date * interval '1 day') >= current_date
您不需要pl / sql
SELECT acquired,
relative_date,
specific_date,
valid_type,
CASE WHEN specific date = "date" -- starts here
THEN specific date
ELSE acquired + cast('1 months' as interval)END
AS expiration_date -- end here
FROM person_drivers_license
WHERE (valid_type = 'days'
AND (EXTRACT(epoch
FROM acquired) - EXTRACT(epoch
FROM now()))/86400 + relative_date > 0)
OR (valid_type = 'DATE'
AND specific_date >= now()));
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