以整數/ string取輸入並將其存儲在數組中

Question

我將如何使用Integer用戶輸入（例如502並將其存儲為數組形式（如arr[0]=5 ， arr[1]=0,arr[2]=2並分別進行訪問。

Answer 1

char[] charArray = String.valueOf(inputInt).toCharArray();

Answer 2

您可以嘗試以下方法：

char[] chars = String.valueOf(520).toCharArray(); // it is the cahr array
// if you want to convert it integer array you can it as below
int[] array = new int[chars.length];
for (int i = 0; i < array.length; i++) {
    array[i] = chars[i];
}
System.out.println("array = " + Arrays.toString(chars));

它是輸出：

array = [5, 2, 0]

Answer 3

您可以通過使用Integer.toString()函數將Integer轉換為String ，然后使用String.toCharArray()函數來將String轉換為char[] 。

public class Program {

    public static void main(String[] args) {
        // Declare your scanner
        Scanner sc = new Scanner(System.in);

        // Waits the user to input a value in the console
        Integer integer = sc.nextInt();

        // Close your scanner
        sc.close();

        // Put your string into a char array
        char[] array = integer.toString().toCharArray();

        // Print the result
        System.out.println(Arrays.toString(array));
    }
}

輸入： 502

輸出： [5, 0, 2]

Answer 4

public class MyClass {

    public static int[] toArray(String input) {
        // 1) check if the input is a numeric input
        try {
            Integer.parseInt(input);
        } catch (NumberFormatException e) {
            throw new IllegalArgumentException("Input \"" + input + "\" is not an integer", e);
        }

        // 2) get the separate digit characters of the input
        char[] characters = input.toCharArray();
        // 3) initialize the array where we put the result
        int[] result = new int[characters.length];
        // 4) for every digit character
        for (int i = 0; i < characters.length; i++) {
            // 4.1) convert it to the represented digit as int
            result[i] = characters[i] - '0';
        }

        return result;
    }

}