在Objective C中解析復雜的JSON（導航其生成的對象的層次結構）

Question

我正在開發基於學校菜單和菜品的應用程序，其中卡住的是解析復雜/嵌套的json

示例Json URL： Json數據

到目前為止，我已經按照下面的代碼所述使用SBJSON完成了此操作 ：

dispatch_async(dispatch_get_main_queue(),^ {

    Reachability *reachability = [Reachability reachabilityForInternetConnection];
    NetworkStatus networkStatus = [reachability currentReachabilityStatus];
    if (networkStatus == NotReachable) {
        [self.view setUserInteractionEnabled:YES];
        [HUD hideUIBlockingIndicator];

    }

    else
    {

        Url =[NSString stringWithFormat:@"http://private-e8e699-yumyummi.apiary-mock.com/districts/115/schools/43/menus/"];
        checkData =[[NSMutableArray alloc]init];
        URLRequest = [NSURLRequest requestWithURL:[NSURL URLWithString:[Url stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding]]];
        NSURLResponse *response = nil;
        NSError  *error = nil;
        NSData  *data = [NSURLConnection sendSynchronousRequest:URLRequest returningResponse:&response error:&error];
        NSString* newStr = [[NSString alloc] initWithData:data encoding:NSUTF8StringEncoding];
        SBJsonParser* parser = [[SBJsonParser alloc] init];

        NSError *jsonError;
        if(jsonError == nil)
        {
            id json = [NSJSONSerialization JSONObjectWithData:data options:0 error:&jsonError];


            NSLog(@"%@",json);

            NSDictionary *data = [json objectForKey:@"data"];            
    }
});

Answer 1

如果您的問題是您不知道json中數據的確切結構，則可以使用以下方法：

if([json isKindOfClass:[NSDictionnary class]) {
    // actions for a dictionnary
    id branch = json[@"your key"];
} else if([json isKindOfClass:[NSArray class]) {
    // actions for an array
    id branch = json[index];
}

另外， if(jsonError == nil)沒有意義，您可以在執行[NSJSONSerialization JSONObjectWithData:data options:0 error:&jsonError];