收到iOS推送通知，但沒有徽章值

Question

在我的iOS Swift應用中，我可以使用以下php代碼發送推送通知：

$ctx = stream_context_create();
stream_context_set_option($ctx, 'ssl', 'local_cert', 'ck.pem');
stream_context_set_option($ctx, 'ssl', 'passphrase', 'APPNAME');

// Open a connection to the APNS server
$fp = stream_socket_client('ssl://gateway.sandbox.push.apple.com:2195', $err, $errstr, 60, STREAM_CLIENT_CONNECT|STREAM_CLIENT_PERSISTENT, $ctx);

if (!$fp) 
{
    exit("Failed to connect: ".$err." ".$errstr." ". PHP_EOL);
}

$body['aps'] = array('alert' => 'This is a test', 'badge' => "1", 'sound' => 'default');
$payload = json_encode($body);
$msg = chr(0) . pack('n', 32) . pack('H*', DEVICE_TOKEN) . pack('n', strlen($payload)) . $payload;
$result = fwrite($fp, $msg, strlen($msg));

我成功接收到帶有聲音的消息，但我的應用程序圖標沒有徽章值。

Answer 1

您正在嘗試使用字符串值設置徽章：

$body['aps'] = array('alert' => 'This is a test', 'badge' => "1", 'sound' => 'default');

根據Apple文檔中有關有效負載密鑰的描述，與密鑰badge關聯的值必須為數字。 將其替換為整數值：

$body['aps'] = array('alert' => 'This is a test', 'badge' => 1, 'sound' => 'default');

Answer 2

使用'badge' => 1而不是'badge' => "1"

Answer 3

嘿@GhostStack確保您必須在applicationDodFinishLaunchingWithOptions方法中注冊警報/聲音和徽章

[[UIApplication sharedApplication] registerForRemoteNotificationTypes:
 (UIRemoteNotificationTypeBadge | UIRemoteNotificationTypeSound | UIRemoteNotificationTypeAlert)];