兩個日期與時間模塊之間的Python差異

Question

有沒有辦法與時間而不是日期時間做時差，這就是我喜歡做的事情：

date1 = time.strptime('02/03/2016 16:01:55', '%d/%m/%Y %H:%M:%S')
date2 = time.localtime(time.time())
print date2 - date1

但是我只得到錯誤：

TypeError: unsupported operand type(s) for -: 'time.struct_time' and 'time.struct_time'

Answer 1

您可以使用time.mktime()來獲得，因為從那個時代的秒數time_struct ：

date = time.strptime('02/03/2016 16:01:55', '%d/%m/%Y %H:%M:%S')
seconds_since_epoch = time.mktime(date)
difference = time.time() - seconds_since_epoch
print time.local_time(difference)

Answer 2

希望這可以幫助

>>> from datetime import datetime
>>>
>>>
>>> d1 = datetime.strptime('02/03/2016 16:01:55', '%d/%m/%Y %H:%M:%S')
>>> d1
datetime.datetime(2016, 3, 2, 16, 1, 55)
>>> d2 = datetime.now()
>>> d1
datetime.datetime(2016, 3, 2, 16, 1, 55)
>>> d2
datetime.datetime(2016, 3, 3, 18, 7, 14, 931872)
>>> d2 - d1
datetime.timedelta(1, 7519, 931872)
>>> (d2 - d1).seconds
7519
>>> (d2 - d1).days
1