將值推入PHP中的數組
[英]Pushing values into array of in php
問題描述
嗨，我正在嘗試將值從輸入推入數組。 我是php的初學者，這是我的任務。 我試圖制定一個時間表
星期一=該小時數周二=該小時數等
但是我在此過程中感到困惑。
<?php
if (isset($_POST['submit'])){
$hours =array();
$hours[] =$_POST['mod1'];
$hours[] =$_POST['mod2'];
$hours[] =$_POST['mod3'];
$hours[] =$_POST['tues1'];
$hours[] =$_POST['tues2'];
$hours[] =$_POST['tues3'];
$hours[] =$_POST['wed1'];
$hours[] =$_POST['wed2'];
$hours[] =$_POST['wed3'];
$wkday = array("Monday" => 0, "Tuesday" => 0, "Wednesday" => 0);
$i = 0;
foreach ($hours as $value){
if(i<3){
$wkday[Monday] = $wkday[Monday] + $value;
} else if(i<6){
$wkday[Tuesday] = $wkday[Tuesday] + $value;
} else if(i<9){
$wkday[Wednesday] = $wkday[Wednesday] + $value;
}
$i++;
}
foreach($wkday as $key => $value) {
echo "Day: $key; Hours Worked: $value <br /> \n";
}
}
?>
5 個解決方案
解決方案1
0 2016-03-04 23:20:40
一種更快的方法是執行以下操作：
<?php
if (isset($_POST['submit'])){
$hours =array();
$hours['Monday'] += (float)$_POST['mod1'];
$hours['Monday'] += (float)$_POST['mod2'];
$hours['Monday'] += (float)$_POST['mod3'];
$hours['Tuesday'] += (float)$_POST['tues1'];
$hours['Tuesday'] += (float)$_POST['tues2'];
$hours['Tuesday'] += (float)$_POST['tues3'];
$hours['Wednesday'] += (float)$_POST['wed1'];
$hours['Wednesday'] += (float)$_POST['wed2'];
$hours['Wednesday'] += (float)$_POST['wed3'];
foreach($hours as $key => $value)
echo "Day: $key; Hours Worked: $value <br /> \n";
}
?>
只是基於$_POST浮動val進行添加，然后像以前一樣回顯。
解決方案2
0 2016-03-04 23:37:59
一種方法是定義一個數組，將日期名稱映射到您用於輸入名稱的縮寫。
$days = array('mod' => 'Monday', 'tues' => 'Tuesday', 'wed' => 'Wednesday');
然后，您可以使用如下嵌套循環來填充$wkday數組：
foreach ($days as $key => $day) { // outer loop iterates over 'mod', 'tues', 'wed'
for ($i=1; $i <= 3; $i++) { // inner loop iterates over 1, 2, 3
$wkday[$day] += $_POST["$key$i"]; // $key$i gives 'mod1' etc.
}
// You can echo as you create the array so you don't have to loop again.
echo "Day: $day; Hours Worked: $wkday[day]<br>\n";
}
解決方案3
0 已采納 2016-03-04 23:40:44
如果可以修改HTML表單，建議您以這種方式更改輸入名稱：
<input name="hours[Monday][]">
<input name="hours[Monday][]">
<input name="hours[Monday][]">
<input name="hours[Tuesday][]">
<input name="hours[Tuesday][]">
<input name="hours[Tuesday][]">
(...)
然后，在您的php代碼中，您可以簡單地編寫以下代碼：
if( isset( $_POST['submit'] ) )
{
$wkday = array( 'Monday' => 0, 'Tuesday' => 0, ... );
foreach( $wkday as $key => $val )
{
$wkday[$key] = array_sum( $_POST['hours'][$key] );
echo "Day: $key; Hours Worked: {$wkday[$key]} <br /> \n";
}
}
另請注意 -參考您的原始代碼：
- 您必須使用
$來引用變量：因此，$i而不是i； -
$wkday[Monday]（和代碼中的類似內容）不正確：Monday被解釋為常量。 在您的情況下，這將起作用，因為沒有Monday常量，但是如果存在常量，那么您將得到不希望的結果。 使用$wkday['Monday']代替。
解決方案4
0 2016-03-07 22:10:03
這是我的html：
<body>
<h1 class="center">Scheduling</h1>
<div class="table" style="border: solid;">
<form class='center' method='POST' action='test2.php'>
<h1> Employee Schedule</h1>
Name: <input type="text" name="Nam" required=" " />
Department: <input type="text" name="Dept" required=" " />
Title: <input type="text" name="title" required=" " />
<h2> Weekdays </h2>
Monday: <input type="number" name="hours[Monday][]" value="0" require="<8" />
<input type="number" name="hours[Monday][]" value="0" require="<8" />
<input type="number" name="hours[Monday][]" value="0" require="<8" />
Tuesday: <input type="number" name="hours[Tuesday][]" value="0" require="<8" />
<input type="number" name="hours[Tuesday][]" value="0" require="<8" />
<input type="number" name="hours[Tuesday][]" value="0" require="<8" />
Wednesday: <input type="number" name="hours[Wednesday][]" value="0" require="<8" />
<input type="number" name="hours[Wednesday][]" value="0" require="<8" />
<input type="number" name="hours[Wednesday][]" value="0" require="<8" />
Thursday: <input type="number" name="hours[Thursday][]" value="0" require="<8" />
<input type="number" name="hours[Thursday][]" value="0" require="<8" />
<input type="number" name="hours[Thursday][]" value="0" require="<8" />
Friday: <input type="number" name="hours[Friday][]" value="0" require="<8" />
<input type="number" name="hours[Friday][]" value="0" require="<8" />
<input type="number" name="hours[Friday][]" value="0" require="<8" />
Saturday: <input type="number" name="hours[Saturday][]" value="0" require="<8" />
<input type="number" name="hours[Saturday][]" value="0" require="<8" />
<input type="number" name="hours[Saturday][]" value="0" require="<8" />
Sunday: <input type="number" name="hours[Sunday][]" value="0" require="<8" />
<input type="number" name="hours[Sunday][]" value="0" require="<8" />
<input type="number" name="hours[Sunday][]" value="0" require="<8" />
<input type="submit" name="submit" value="Calculate" />
</form>
這是我的PHP：
<?php
$Nam = $_POST['Nam'];
$Dept = $_POST['Dept'];
$Title = $_POST['title'];
if( isset( $_POST['submit'] ) )
{
$wkday = array( 'Monday' => 0, 'Tuesday' => 0, 'Wednesday' => 0, 'Thursday' => 0, 'Friday' => 0, 'Saturday' => 0, 'Sunday' => 0);
echo "Employee name: $Nam <br /> \n";
echo "Department: $Dept <br /> \n";
echo "Title: $Title <br /> \n";
foreach( $wkday as $key => $val )
{
$wkday[$key] = array_sum( $_POST['hours'][$key] );
echo "Day: $key; Hours Worked: {$wkday[$key]} <br /> \n";
}
}
?>
解決方案5
0 2016-03-07 22:39:51
我不認為我完成了自己的承諾：
創建包含復選框和其他表單元素的表單以創建數組。 AND array（）函數創建索引數組和關聯數組。
確保訪問索引數組和關聯數組中的單個數組元素
使用PHP將值推入多維數組
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