[英]How to insert a record in MySQL with PHP with an HTML form
我已經在html中創建了一個表單,我希望將表單中輸入的數據發送到XAMMP中的mysql數據庫。 我創建了數據庫,表和管理與數據庫和數據條目的連接的connection.php文件,但是當我嘗試時,出現以下錯誤:
“致命錯誤:未捕獲的錯誤:調用C:\\ xampp \\ htdocs \\ example \\ connectivity.php:8中未定義的函數mysql_connect()堆棧跟蹤:#0 {main}拋出了C:\\ xampp \\ htdocs \\ example \\ connectivity。第8行的php”
我發布了我編寫的所有代碼。 有人知道我錯了嗎?
這是index.html的形式
<!DOCTYPE HTML>
<html>
<head>
<title>Contact Us</title>
<link rel="stylesheet" type="text/css" href="style.css">
<?php include("connectivity.php"); ?>
</head>
<body>
<div id="contact">
<h3>Contact Us For Any Query</h3>
<form method="POST" action="connectivity.php">
Name
<br>
<input type="text" name="name">
<br> Email
<br>
<input type="text" name="email">
<br> Message
<br>
<textarea rows="10" cols="50" maxlength="100" name="message"></textarea>
<br>
<input type="submit" value="Send Message">
</form>
</div>
</body>
</html>
然后用於定義數據庫和表的代碼:
CREATE DATABASE practice;
USE practice;
CREATE TABLE contact
(
contactID INT(9) NOT NULL auto_increment,
contactName VARCHAR(40) NOT NULL,
contactEmail VARCHAR(40) NOT NULL,
message VARCHAR(250) NOT NULL,
PRIMARY KEY(contactID)
);
最后,connection.php文件:
<?php
//connecting to the database
define('DB_HOST', 'localhost');
define('DB_NAME', 'practice');
define('DB_USER','root');
define('DB_PASSWORD','');
$con=mysql_connect(DB_HOST, DB_USER, DB_PASSWORD) or die("Failed to connect to MySQL: " . mysql_error());
$db=mysql_select_db(DB_NAME,$con) or die("Failed to connect to MySQL: " . mysql_error());
//inserting Record to the database
$name = $_POST['name'];
$email = $_POST['email'];
$message = $_POST['message'];
$query = "INSERT INTO contact(contactName,contactEmail,message)VALUES('$name','$email','$message')";
$result = mysql_query($query);
if($result)
{
echo "Successfully updated database";
}
else
{
die('Error: '.mysql_error($con));
}
mysql_close($con);
?>
PS:我安裝了最新版本的XAMMP(5.6.15)
$ con = mysqli_connect(DB_HOST,DB_USER,DB_PASSWORD,## TABLE NAME ##)或die(“無法連接到MySQL:”。mysql_error());
$ query =“在聯系人中插入INERT(contactName,contactEmail,message)VALUES('$ name','$ email','$ message')”; $結果= mysqli_query($ con,$ query);
首先,您會看到您的phpinfo:
<?php
phpinfo();
?>
然后在這里看到, php_mysql
是啟用還是禁用?
如果沒有php_mysql
,請更改php.ini
文件:Uncomment extension=php_mysql.dll
如果您使用的是xampp
的最新版本,則必須使用PDO或MySQLi。
您必須將代碼更改為類似的內容。
您的連接頁面
<?php
$db = new PDO('mysql:host=localhost;dbname=practice;charset=utf8',
'root',
'',
array(PDO::ATTR_EMULATE_PREPARES => false,
PDO::ATTR_ERRMODE => PDO::ERRMODE_EXCEPTION));
?>
<?php
if (isset($_POST['name'])) {
$name = $_POST['name'];
$email = $_POST['email'];
$message = $_POST['message'];
$stmt = $db->prepare("INSERT INTO `contact` (contactName,contactEmail,message)
VALUES (:name, :email, :message)");
$stmt->bindParam(':name', $name);
$stmt->bindParam(':email', $email);
$stmt->bindParam(':message', $message);
$stmt->execute();
echo 'added';
}
?>
您的首頁
<!DOCTYPE HTML>
<html>
<head>
<title>Contact Us</title>
<link rel="stylesheet" type="text/css" href="style.css">
</head>
<body>
<div id="contact">
<h3>Contact Us For Any Query</h3>
<form method="POST" action="connectivity.php">
Name
<br>
<input type="text" name="name">
<br> Email
<br>
<input type="text" name="email">
<br> Message
<br>
<textarea rows="10" cols="50" maxlength="100" name="message"></textarea>
<br>
<input type="submit" value="Send Message">
</form>
</div>
</body>
</html>
希望這可以幫助
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