嵌套if語句c ++中的預期表達式錯誤

Question

我在嵌套的 if else 語句中不斷收到預期的表達式錯誤。 我不明白問題是什么，因為我在代碼中還有其他語句，它們的格式（據我所知）與不會產生錯誤的方式完全相同！

這是針對第一年 c++ 課程的作業，該課程根據用戶輸入數據計算保齡球分數。

#include <iostream>

using namespace std;

int main() {

    // Set Variables
    int userin_1;
    int userin_2;
    int userin_3;
    int combined2_3;
    int score;


    // Query User

    cout << "Welcome to Josh's Bowling Score Calculator! " << "Please enter your three scores. "
    << "They should be between 0 and 10." << endl << endl;

    cin >> userin_1 >> userin_2 >> userin_3;

    // Verify input data

    if (userin_1 <= 10 && userin_2 <=10 && userin_3 <=10)
        userin_1 = userin_1;
        else cout << endl << "Input Error: You cannot score greater than 10 in one turn! :|" << endl;

    if (userin_1 >= 0 && userin_2 >=0 && userin_3 >=0)
        userin_1 = userin_1;
    else cout << endl << "Input Error: You cannot score less than 0 in one turn! :|" << endl;

    if (userin_1 == 10)
        userin_1 = userin_1;
        else if (userin_1 + userin_2 <= 10)
            cout << "Input Error: You can't score more than 10 on your first two throws unless your first throw is a strike! "
            << endl;

    if (userin_2 == 10)
        userin_2 = userin_2;
    else if (userin_2 + userin_3 <= 10)
        cout << "Input Error: You can't score more than 10 on your first two throws unless your first throw is a strike! "
        << endl;

    // Calculate Score

    combined2_3 = userin_2 + userin_3;

    if (userin_1 + userin_2 < 10)
    {
        score = userin_1 + userin_2;
        cout << "Because you scored less than 10 on your first two throws, your last score doesn't count :[ "
    << "Your score is: " << score << endl;
    }
        else
        {
        if (userin_1 == 10 && userin_2 == 10 && userin_3 == 10)
        score = userin_1 + userin_2 + userin_3;
        cout << "Wowow 3 strikes! Your score is " << score << endl;
        }
            else
            {
            if (userin_1 == 10 && userin_2 == 10)
            score = userin_1 + userin_2 + userin_3;
            cout << "Two strikes! Your score is " << score << endl;
            }
                else
                {
                if (userin_1 == 10 && userin_2 + userin_3 >= 10)
                    cout << "It's not possible to score greater than 10 on your last two throws, unless your first throw is a strike :| " << endl;
                }
                    else
                    {
                        if (userin_1 == 10 && combined2_3 >= 10)
                            score = userin_1 + userin_2 + userin_3;
                        cout << "Nice, a strike! Your score is " << score << endl;
                    }
                        else
                        {
                            if (userin_1 == 0 && userin_2 == 0 && userin_3 == 0)
                                cout << "Donny, you're out of your element. All zeroes." << endl << endl;
                        }


    // Closing Statement

    cout << endl << "Thanks for bowling with me, hope you have a great day";




}

Answer 1

編輯：我錯了，這是錯誤：

    else
    {
    if (userin_1 == 10 && userin_2 == 10 && userin_3 == 10)
    score = userin_1 + userin_2 + userin_3;
    cout << "Wowow 3 strikes! Your score is " << score << endl;
    }
        else
        {
        if (userin_1 == 10 && userin_2 == 10)
        score = userin_1 + userin_2 + userin_3;
        cout << "Two strikes! Your score is " << score << endl;
        }

第二個else沒有關聯的if之前。 將if移動到相應的else子句中。

    else if (userin_1 == 10 && userin_2 == 10 && userin_3 == 10) {
        score = userin_1 + userin_2 + userin_3;
        cout << "Wowow 3 strikes! Your score is " << score << endl;
    } else if (userin_1 == 10 && userin_2 == 10) {
        score = userin_1 + userin_2 + userin_3;
        cout << "Two strikes! Your score is " << score << endl;
    }

但是，這里更嚴重的問題是您處理任務的方式。 此任務有太多嵌套的if語句。 你在條件上重復幾次，而正確的方法是只檢查條件一次，然后分支。

另外，像這樣的語句

if (userin_1 <= 10 && userin_2 <=10 && userin_3 <=10)
    userin_1 = userin_1;

沒有意義，您應該檢查相反的內容並完全跳過else子句。

您還應該使用適當的縮進，因為它極大地有助於提高代碼可讀性並有助於避免此類錯誤。